Question

我创建了一个获取文本并计算其中的单词数的应用。我的应用程序具有用于输入文本的“编辑文本”和用于显示单词数的“文本视图”。我必须对我的应用程序提出问题：1.标点符号（例如“！？。”，其后有空格）被视为不应该包含的单词，并且2.从编辑文本中删除文本后，我的文本视图显示1（即数字）字词，但编辑文本为空。请帮忙。

这是我的代码：

package com.farmani.wordcounter;

import android.annotation.SuppressLint;
import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.text.Editable;
import android.text.TextWatcher;
import android.widget.EditText;
import android.widget.TextView;

public class MainActivity extends AppCompatActivity {

TextView tv;
EditText et;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

     tv = findViewById(R.id.tv);
     et = findViewById(R.id.et);

    et.addTextChangedListener(new TextWatcher() {
        @Override
        public void beforeTextChanged(CharSequence s, int start, int count, int after) {

        }

        @SuppressLint("SetTextI18n")
        @Override
        public void onTextChanged(CharSequence s, int start, int before, int count) {

            String text = et.getText().toString();
            text = text.replace("\n"  , " ");
            String[] textArray = text.split(" +|,|\\.");
            tv.setText("Number of Words: " + textArray.length);
        }

        @Override
        public void afterTextChanged(Editable s) {

        }
    });



}
}

Answer 1

尝试一下：

final String text = "Hello! This is some text with words.";

final String[] split = text.split("\\W"); // Split by "non-word" characters

int wordCnt = 0;
for (String s : split) {
  if (!s.isEmpty()) { // If two adjacent non-word characters are encountered the string in between is empty, so we don't count it.
    wordCnt++;
  }
}

另请参阅https://developer.android.com/reference/java/util/regex/Pattern

标点符号（RegExp）计为单词

1 个答案: