测试Java代码以进行失败测试的循环

Question

enter image description here / **检查每个单元格的边框是否与          *其邻居。例如，如果一个牢房没有东墙，          *那么它在东面的邻居应该没有 west 墙。          *          *具体来说：对于网格中的每个单元格以及每个方向，          *如果以下情况，该单元可能在该方向上有墙          *墙在网格的边缘，并且必须有墙          *如果它的邻居在那个方向          *在那个方向上有一个对应的墙。          *          * @return网格中的单元格是否具有有效的边框值。          * /         public boolean bordersAreValid（）{             布尔结果= true;             for（int j = 0; j

                   if (i==0 && !this.cells[j][i].hasWest()) {
                       result = false;
                   }

                   if (j== this.cells.length -1 && this.cells[j][i].hasSouth()) {
                       result = false;
                   }

                   if (i== this.cells.length -1 && this.cells[j][i].hasEast()) {
                       result = false;
                   }
               } else {
                   Cell northneighbour; Cell southneighbour; Cell eastNeighbour; Cell westNeighbour;
                   northneighbour = this.cells[j-1][i];
                   southneighbour = this.cells[j+1][i];
                   eastNeighbour  = this.cells[j][i+1];
                   westNeighbour  = this.cells[j][i-1];

                   if (this.cells[j][i].hasNorth() && !northneighbour.hasSouth() ){
                       result = false;
                   }

                   if (this.cells[j][i].hasEast() && !northneighbour.hasWest() ){
                       result = false;
                   }

                   if (this.cells[j][i].hasWest() && !northneighbour.hasEast() ){
                       result = false;
                   }

                   if (this.cells[j][i].hasSouth() && !northneighbour.hasNorth() ){
                       result = false;
                   }
               }
            }
        }

        return result;
    }