Question

我已经看到并尝试了Tkinter StringVar error中的答案，但是它仍然没有解决任何问题，我正在基于文本的rpg（我知道python不一定是游戏的最佳选择，并且它可能很不方便），而我试图制作一个if语句来保持语法正确。这是到目前为止的代码

import tkinter as tk
import random
from tkinter import*


class Nirvana:
    def __init__(self, master):
        self.master = master
        master.title("Nirvana")

        happen = StringVar()

        self.event = Message(master, textvariable= happen)
        self.event.grid(row=0)

        self.b1 = Button(master, text= "Continue", command= self.go)
        self.b1.grid(row=1)

        encounter = StringVar()
        enc = encounter.get()
        hap = happen.get()

    def go(self):
        encounter.set(random.choice(hostiles1 + hostiles2))
        if (enc[0]) is "a" or "e" or "i" or "o" or "u":
            happen.set("You have encountered an", enc)
        else:
            happen.set("You have encountered a", enc)

d = ("dragon")
w = ("wolf")
o = ("ogre")

hostiles1 = [d, w]
hostiles2 = [o]

root = Tk()
root.geometry("500x500")
my_gui = Nirvana(root)
root.mainloop()

这是错误

Exception in Tkinter callback
Traceback (most recent call last):
  File "/Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/tkinter/__init__.py", line 1702, in __call__
    return self.func(*args)
  File "Tbr.py", line 22, in go
    encounter.set(random.choice(hostiles1 + hostiles2))
NameError: name 'encounter' is not defined

Answer 1

您需要将StringVar对象分配给属性：

import tkinter as tk
import random


class Nirvana:
    def __init__(self, master, hostiles1, hostiles2):
        self.master = master
        self.hostiles1 = hostiles1
        self.hostiles2 = hostiles2
        master.title("Nirvana")

        self.happen = tk.StringVar()

        self.event = tk.Message(master, textvariable=self.happen)
        self.event.grid(row=0)

        self.b1 = tk.Button(master, text="Continue", command=self.go)
        self.b1.grid(row=1)

        self.encounter = tk.StringVar()

    def go(self):
        self.encounter.set(random.choice(self.hostiles1 + self.hostiles2))
        enc = self.encounter.get()
        a = "an" if enc[0] in ("a", "e", "i", "o", "u") else "an"
        self.happen.set("You have encountered {} {}".format(a, enc))

def main():
    d = "dragon"
    w = "wolf"
    o = "ogre"

    hostiles1 = [d, w]
    hostiles2 = [o]

    root = tk.Tk()
    root.geometry("500x500")
    my_gui = Nirvana(root, hostiles1, hostiles2)
    root.mainloop()

if __name__ == '__main__':
    main()

获取NameError尝试访问我的tkinter stringvar

1 个答案: