Question

我有任务要做

编写一个shell脚本evenparam.sh，它具有偶数个命令行参数，因此它具有以下语法   evenparam.sh para1 para2 [para3 para4] ...   该脚本应生成以下形式的输出：para1 = para2，para3 => para4，...。   如果未正确调用程序，请在stderr上发出用法消息，并以大于1的返回值结束脚本。



anz=$#
counter=1
if [ $(($# % 2)) -eq 0 ]; then
    for para in $@; do
        pos1=$counter
        pos2=$(($counter+1))
        echo $pos1=$pos2
        counter=$(($counter+2))
        if [ $counter = $(($# + 1)) ]; then
            exit 0
        fi
    done
fi

anz=$# counter=1 if [ $(($# % 2)) -eq 0 ]; then for para in $@; do pos1=$counter pos2=$(($counter+1)) echo $pos1=$pos2 counter=$(($counter+2)) if [ $counter = $(($# + 1)) ]; then exit 0 fi done fi

我心中没有任何信息可做有人可以帮我吗？

Answer 1

以下演示功能，请参见bash手册man bash，以供参考

#!/bin/bash

(( $#%2==0 )) || {
    echo "usage: $0 para1 para2 [para3 para4] ..."
    exit 1
}

# either using array
args=( "$@" )
for (( i=0;i<$#;i+=2 )); do
    echo "${args[i]} = ${args[i+1]}"
done

# or consuming arguments
while (( $#>0 )); do
    echo "$1 = $2"
    shift 2
done

# otherwise because printf has loop, just
printf "%s = %s\n" "$@"

Answer 2

./ test1.sh para1 para2 [para3 para4]＃如果我在终端中键入

输出是这样的：

 para1 = para2
 [ = para3
 para4 ] =

我使用您的代码

args=( "$@" )
for (( i=0;i<$#;i+=2 )); do
echo "${args[i]} = ${args[i+1]}"
done

具有参数输出的Bash脚本

2 个答案: