Question

我在Rest Web服务中使用RxJava2 Observable.fromIterable（）。我的示例iterable由三个元素组成，但是我的非阻塞休息服务仅返回三个元素中的一个。

class ToDoDaoImpl implements ToDoDao {
  Map<String, ToDo> toDos;
  ...
  public Observable<ToDo> readAll() {
    return Observable.fromIterable(toDos.entrySet().stream().map(entry -> entry.getValue()).collect(Collectors.toList()));
  }
}

当我从我的Non-Blocking Rest库中调用readAll（）方法时，我只在三个元素上得到一个元素：

@Api(path = "/api/v2/read", method = "GET", produces = "application/json")
Action readAllToDos = (HttpServletRequest request, HttpServletResponse response) -> {
    Observable.just(request)
            .flatMap(req -> toDoDao.readAll())
            .subscribe(output  -> toJsonResponse(request, response, new ResponseDto(200, output)),
                       error   -> toJsonResponse(request, response, new ResponseDto(200, error))
            );
};

我的输出：

{
"status": 200,
"response": {
    "id": "5dc74dd8-1ea9-427e-8bb7-482cc6e24c71",
    "title": "learn ReactiveJ",
    "description": "learn to use ReactiveJ library",
    "date": {
        "year": 2018,
        "month": 10,
        "day": 29
    }
},
"datetime": "Oct 29, 2018 4:19:51 PM"
}

如果我将我的Dao称为“非反应性”等效物，反而会得到我期望的结果：

{
"status": 200,
"response": [
    {
        "id": "25cbe3bf-12be-42e4-82ce-d4780f6469f6",
        "title": "study reactive",
        "description": "learn reactive programming",
        "date": {
            "year": 2018,
            "month": 10,
            "day": 29
        }
    },
    {
        "id": "51879241-f005-43fa-80fb-78386b663cb7",
        "title": "learn ReactiveJ",
        "description": "learn to use ReactiveJ library",
        "date": {
            "year": 2018,
            "month": 10,
            "day": 29
        }
    },
    {
        "id": "80a07c1b-2317-4eb8-9a39-ac35260f37a2",
        "title": "exercise",
        "description": "do some exercises",
        "date": {
            "year": 2018,
            "month": 10,
            "day": 29
        }
    }
],
"datetime": "Oct 29, 2018 4:37:05 PM"
}

Answer 1

如果将doOnNext放在订阅之前，您会看到您有多个元素，但是显然JsonResponse只能传递一个。我敢打赌，您的非反应式版本只是将整个List传递给了ResponseDto。

我不确定您为什么要繁琐的工作，但这应该可以工作：

class ToDoDaoImpl implements ToDoDao {
    Map<String, ToDo> toDos;
    // ...
    public Observable<List<ToDo>> readAll() {
        return Observable.fromCallable(() -> new ArrayList<>(toDos.values()));
    }
}

@Api(path = "/api/v2/read", method = "GET", produces = "application/json")
Action readAllToDos = (HttpServletRequest request, HttpServletResponse response) -> 
{
    toDoDao.readAll()
        .subscribe((List<ToDo output)  -> 
            toJsonResponse(request, response, new ResponseDto(200, output)),
                   error   -> 
            toJsonResponse(request, response, new ResponseDto(200, error))
        );
};

从iterable观察并不会打印所有元素

1 个答案: