Question

我有一个查询来获取具有某些关系的产品，但是当添加"orderBy('updated_at', 'desc')时，与产品图像的关系变成一个空数组。

我从：

开始

$products = \App\Product::where('id', '>', 0)
->with('designer')      
->whereIn('id', [$someIds]);

然后，我继续添加与“ whereHas”查询的某些关系（如果我将其删除，则问题仍然存在）

最后，如果我这样做：

  return $products
          ->with('gallery.items')
         ->orderBy('updated_at', 'desc')->paginate($args['count']);

gallery.items数组为空。如果我使用'asc'而不是'desc'，则效果很好。我也尝试过orderByDesc方法，但这是同一回事。

如果更改顺序，在添加“ with”关系之前执行orderBy，它还会为图库图像返回空数组：

  return $products->orderBy('updated_at', 'desc')
     ->with('gallery.items')
     ->paginate($args['count']);

修改：我可以进行更简单的查询来缩小问题范围：

 return $products = \App\Product::take(30)
                  ->orderBy('updated_at', 'desc')
                  ->with('gallery.items') 
                  ->get();

^^这也给出了空的图库项目。如果删除->orderBy('updated_at', 'desc')，则图库项目将按应有的方式显示。同样，“ asc”有效（这是默认排序）。

更新：这是上面的^^查询，以\DB::enableQueryLog()记录：

      {
                           "query": "select * from `products` 
            order by `updated_at` desc limit 30",
                        "bindings": [],
                          "time": 26.46
                        },
                         {
                            "query": "select * from `galleries` where `galleries`.`id`
           in (?, ?, ?, ?, ?, ?,?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, 
    ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)",

                                "bindings": [
                 3970,3971,3973,3974,3975,3976,3977,3978,3979,3980,3981,3982,3983,3984,
                    3985,3986,3987,3988,3989,3990,3991,3992,3993,3994,3995,3996,3997,3998,
                    3999,4000],
                 "time": 3.64
                },
                {
                                        "query": "select `uploads`.*,
                 `gallery_items`.`gallery_id` as `pivot_gallery_id`, 

                `gallery_items`.`upload_id` as `pivot_upload_id`,

                `gallery_items`.`order` as `pivot_order` 

                from `uploads` 

                inner join `gallery_items` on `uploads`.`id` = `gallery_items`.`upload_id`
            where `gallery_items`.`gallery_id` 
            in (?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?,
         ?, ?, ?, ?, ?, ?)",

                                "bindings": [
          3970,3971,3973,3974,3975,3976,3977,3978,3979,3980,3981,3982,
3983,3984,3985,3986,3987,3988,3989,3990,3991,3992,3993,3994,3995,
3996,3997,3998,3999,4000],

                      "time": 48.92

修改2： Gallery模型上的gallery.items关系是这样的：

items(){
      return $this->belongsToMany('\App\Upload', 'gallery_items','gallery_id','upload_id')
                 ->withPivot('order');
}

雄辩的-当“ orderBy desc”时产生空模型关系

0 个答案: