Question

给定一个父标签集，每个标签具有多个子标签集。如何创建链接“堂兄”内容的<a href="#??"></a>？这是我到目前为止所尝试的，我并不认为它是正确的！我试图从tab id =＃A.1跳到堂兄＃E.2的每个链接都没有成功。

脚本：

 <script> $(document).ready(function(event){
        var tabs = $("#parentTabSet, #childSet1, #childSet2").tabs();
    //here's what i've tried so far:
        $(".interTabLink").click(function(event){
    //this gets the `<ul><li><a href="#someId">tab user wants to see</a></li></ul>`
          var ulLink =$(".anytabset").find("[href='"+$(this).attr("href")+"']");
//filter the 'var tabs' array to only have the tabset we want.
          tabs.filter("#"+ulLink.closest("div").attr("id")).tabs("select", $(this).attr("href"));
        });
      });
    </script>

HTML：

<body>
<div id="parentTabSet" class="anyTabSet">
 <ul>
  <li><a href="#A">parent A</a></li>
  <li><a href="#B">parent B</a></li>
  <li><a href="#C">parent C</a></li>
  <li><a href="#D">parent D</a></li>
  <li><a href="#E">parent E</a></li>
 </ul>
 <div id="A">
   <div id="childset1" class="anyTabSet">
     <ul>
       <li><a href="#A.1">foo</a></li>
       <li><a href="#A.2">bar</a></li>
      </ul>
      <div id="#A.1"><p>insert your latin here</p></div>
      <div id="#A.2">
<!--- this will link to cousin #E.2, with parent tab E --->
<a href="#E.2" class="interTabLink">more information here</a>
      </div>
   </div>
 </div>
<div id="B">
<p>insert your latin here</p>
 </div>
<div id="C">
<p>insert your latin here</p>
 </div>
<div id="D">
<p>insert your latin here</p>
 </div>
<div id="E">
<div id="childset2" class="anyTabSet">
     <ul>
       <li><a href="#E.1">foo</a></li>
       <li><a href="#E.2">bar</a></li>
      </ul>
      <div id="#E.1">stuff</div>
      <div id="#E.2">here</div>
   </div>
 </div>
</div>
</body>

Answer 1

这样的事情会起作用：

var mytabs = $('.anyTabSet').tabs();

$(".interTabLink").click(function( event ){
    event.preventDefault();
    var id = $(this).attr("href");
    var tab = mytabs.find("li [href='"+id+"']");
    if ( tab.length ) {
        var tabset = tab.closest('.anyTabSet').tabs("select", id);
        if ( tabset.length ) {
            id = id.replace(/_[0-9]/,'');
            tabset.parents('.anyTabSet').tabs("select", id );    
        }
    }
});

工作示例：http://jsfiddle.net/petersendidit/uz7d5/

使用Jquery-ui选项卡，使用父选项卡集和子选项卡集，如何在选项卡'cousins'之间进行链接？

1 个答案: