Question

我有一个返回包装结果的API，我想用一个通用包装而不是20个包装。

但是，我无法将结果值转换为通用类型。这是代码：

根据api的响应：

override fun onResponse(call: Call, response: Response) {

        val userResponse = response.getResultAs<UserResponse>()

        userResponse?.let { user ->
            App.shared.userSettings.edit().putString(UserSettingsKeys.ACTIVE_USER.key,
                    ObjectMapper().writeValueAsString(user)).apply()
            App.shared.userSettings.edit().putString(UserSettingsKeys.TOKEN.key,
                    response.header("Authorization")).apply()
            presenter?.onLoginSuccess(user)
        } ?: presenter?.onLoginFailure("No response returned")
}

结果类的扩展名：

fun <T> Response.getResultAs(): T? {

    this.body()?.string()?.let {
        val mapper = jacksonObjectMapper()
        val obj = JsonParser().parse(it).asJsonObject.toString()
        val baseResponseWrapper: BaseResponseWrapper<T> = mapper.readValue(obj)

        when {
            baseResponseWrapper.errorValues != null -> {
                baseResponseWrapper.logErrorMessage = "invalid credentials"
            }

            baseResponseWrapper.returnVal == null -> {
                baseResponseWrapper.logErrorMessage = "returnVal could not be parsed"
            }

            else -> {
                return baseResponseWrapper.returnVal
            }
        }
    }
    return null
}

响应包装器类：

data class BaseResponseWrapper<T>(

    @field:JsonProperty("returnVal")
    val returnVal: T? = null,

    @field:JsonProperty("errorDescription")
    val errorDescription: String? = null,

    @field:JsonProperty("errorCode")
    val errorCode: Int? = null,

    @field:JsonProperty("errorValues")
    val errorValues: Any? = null,

    var logErrorMessage: String? = null

)

它将数据解析为格式正确的Linked Hash映射，而不是作为我的类。这是我在调试崩溃之前的状态：

baseResponseWrapper.returnVal = {LinkedHashMap@7400}  size = 9  
0 = {LinkedHashMap$LinkedHashMapEntry@7409} "isInfluencer" -> "false"  
1 = {LinkedHashMap$LinkedHashMapEntry@7410} "currentUserBranchUsername" -> "000"  
2 = {LinkedHashMap$LinkedHashMapEntry@7411} "parentUser" -> " size = 4"  
3 = {LinkedHashMap$LinkedHashMapEntry@7412} "profile" -> " size = 3"  
4 = {LinkedHashMap$LinkedHashMapEntry@7413} "currentUserProfile" -> "null"  
5 = {LinkedHashMap$LinkedHashMapEntry@7414} "email" -> "null"  
6 = {LinkedHashMap$LinkedHashMapEntry@7415} "userName" -> "null"  
7 = {LinkedHashMap$LinkedHashMapEntry@7416} "muviId" -> "null"  
8 = {LinkedHashMap$LinkedHashMapEntry@7417} "userId" -> "0000-0000-0000"

这是我的控制台错误：

2018-10-29 12：56：15.401 1916-1962 / com.appshack.livetree E / AndroidRuntime：致命例外：OkHttp Dispatcher 流程：com.appshack.livetree，PID：1916 java.lang.IllegalStateException：已关闭在okio.RealBufferedSource.rangeEquals（RealBufferedSource.java:408）在okio.RealBufferedSource.rangeEquals（RealBufferedSource.java:402）在okhttp3.internal.Util.bomAwareCharset（Util.java:469）在okhttp3.ResponseBody.string（ResponseBody.java:175）在com.appshack.livetree.utililty.extensions.OkHttpResult_getResultAsKt.getResultAs（OkHttpResult + getResultAs.kt：17）在com.appshack.livetree.ui.outside.login.LoginInteractor $ loginResponseCallback $ 1.onResponse（LoginInteractor.kt：43）在okhttp3.RealCall $ AsyncCall.execute（RealCall.java:153）在okhttp3.internal.NamedRunnable.run（NamedRunnable.java:32）在java.util.concurrent.ThreadPoolExecutor.runWorker（ThreadPoolExecutor.java:1133）在java.util.concurrent.ThreadPoolExecutor $ Worker.run（ThreadPoolExecutor.java:607）在java.lang.Thread.run（Thread.java:761）

我不是泛型新手，但是有什么办法可以使这项工作呢？

使用通用类型将响应转换为返回Moddel以反序列化api响应

0 个答案: