根据Teradata中的条件优先级填充列

时间:2018-10-29 10:53:45

标签: teradata partition operator-precedence

我需要根据条件优先级填充一列:

如果O_M不为零(例如:0.34),则在同一列Prev. record中检查TP_N(由O_M排序)如果对于3个或更多使用代码(OD03,OT03,MO03)编码的实例,它为零,那么我应该用当前To_Compute值-O_M填充0.34列。我需要对DT,MNTH,P_ID,A_BR,D_BR,B_BR,DR排序的每个分区(TP_N)重复此操作。我只应该从O_N-(OD03,OT03,MO03)

列中查找这些代码
DT        MNTH  P_ID    A_BR    D_BR B_BR   TP_N    DR  O_M O_N  TO_Compute
9/29/2016   9   QT21    1506    05Y XS-123  487,006 0   0   ?       0
9/29/2016   9   QT21    1506    05Y XS-123  487,007 0   0   OD03    0
9/29/2016   9   QT21    1506    05Y XS-123  487,008 0   0   OD03    0
9/29/2016   9   QT21    1506    05Y XS-123  487,009 0   0   OD03    0
9/29/2016   9   QT21    1506    05Y XS-123  487,010 0   0   OD03    0
9/29/2016   9   QT21    1506    05Y XS-123  487,011 0   0   OD03    0
9/29/2016   9   QT21    1506    05Y XS-123  487,012 0   0   OD03    0
9/29/2016   9   QT21    1506    05Y XS-123  487,013 0   0   OD03    0
9/29/2016   9   QT21    1506    05Y XS-123  487,014 0   0   MO03    0
9/29/2016   9   QT21    1506    05Y XS-123  487,015 0   0   OT03    0
9/29/2016   9   QT21    1506    05Y XS-123  487,016 0   0   OD03    0
9/29/2016   9   QT21    1506    05Y XS-123  487,017 0   0.34    ?   0.34
9/29/2016   9   QT21    1506    05Y XS-123  487,018 0   0   OD03    0
9/29/2016   9   QT21    1506    05Y XS-123  487,019 0   1.03    ?   0
9/29/2016   9   QT21    1506    05Y XS-123  487,020 0   0.3     ?   0
9/29/2016   9   QT21    1506    05Y XS-123  487,021 0   1.25    ?   0
9/29/2016   9   QT21    1506    05Y XS-123  487,022 0   0   OP04    0
9/29/2016   9   QT21    1506    05Y XS-123  487,023 0   10.53   ?   0
9/29/2016   9   QT21    1506    05Y XS-123  487,024 0   0.37    ?   0
9/29/2016   9   QT21    1506    05Y XS-123  487,025 0   0.28    ?   0
9/29/2016   9   QT21    1506    05Y XS-123  487,026 0   0   OD03    0
9/29/2016   9   QT21    1506    05Y XS-123  487,027 0   0   OD03    0
9/29/2016   9   QT21    1506    05Y XS-123  487,028 0   0.6     ?   0
9/29/2016   9   QT21    1506    05Y XS-123  487,029 0   0.38    ?   0
9/29/2016   9   QT21    1506    05Y XS-123  487,030 0   0.4 ?   0
9/29/2016   9   QT21    1506    05Y XS-123  487,031 0   0.35    ?   0
9/29/2016   9   QT21    1506    05Y XS-123  487,032 0   0.45    ?   0
9/29/2016   9   QT21    1506    05Y XS-123  487,033 0   0   OD03    0
9/29/2016   9   QT21    1506    05Y XS-123  487,034 0   0   OD03    0
9/29/2016   9   QT21    1506    05Y XS-123  487,035 0   0   OD03    0
9/29/2016   9   QT21    1506    05Y XS-123  487,036 0   0.3     ?   0.3
9/29/2016   9   QT21    1506    05Y XS-123  487,037 0   0.35    ?   0
9/29/2016   9   QT21    1506    05Y XS-123  487,038 0   0.52    ?   0

但是,如果O_M不为零(例如:0.6-列O_M从底部开始的第11行),我会在同一列{{中检查Prev. record 1}},而我只有2条O_M的上一条记录(对于3个或更多使用代码zero编码的实例,则我应该在(OD03,OT03,MO03)列中填充To_Compute

如果0不为零(例如:O_M的倒数第三行),则在同一列0.3中检查O_M,在这里对于3个或更多使用代码Prev. record编码的实例,它为零,那么我应该用当前O_M值-(OD03,OD03,OD03)填充To_Compute列。

我是TD新手。对此有任何帮助。

2 个答案:

答案 0 :(得分:1)

未经测试,但这应该可以根据您的描述进行操作:

case
   when sum(O_M) -- previous three rows are all 0 (assuming no negative values exist)
        over (partition by ??
              order by TP_N
              rows between 3 preceding and 1 preceding) = 0
    and -- prvious three rows contain any of the searched codes
        sum(case when O_N IN ('OD03','OT03','MO03') then 1 else 0 end)
        over (partition by ??
              order by TP_N
              rows between 3 preceding and 1 preceding) = 3
   then O_M
   else 0
end

答案 1 :(得分:0)

我将为您提供两种可能的解决方案,以决定哪种方法最适合您的情况。第一个比较简单,但是比较繁琐,因为它只是简单地连接到同一个表3次。假设您上面的数据存在于DATASET表中:

select ds1.dt
,ds1.mnth
,ds1.p_id
,ds1.a_br
,ds1.d_br
,ds1.b_br
,ds1.tp_n
,ds1.dr
,ds1.o_m
,ds1.o_n
,case when zeroifnull(ds4.o_m) + zeroifnull(ds3.o_m) + zeroifnull(ds2.o_m) = 0 and ds4.o_n in ('OD03','OT03','MO03') and ds3.o_n in ('OD03','OT03','MO03') and ds2.o_n in ('OD03','OT03','MO03') then ds1.o_m
else 0 end as TO_COMPUTE
from dataset ds1
left join dataset ds2
on ds1.tp_n = ds2.tp_n +1
and ds1.dt = ds2.dt
and ds1.mnth = ds2.mnth
and ds1.p_id = ds2.p_id
and ds1.a_br = ds2.a_br
and ds1.d_br = ds2.d_br
and ds1.b_br = ds2.b_br
and ds1.dr = ds2.dr
left join dataset ds3
on ds1.tp_n = ds3.tp_n +2
and ds1.dt = ds3.dt
and ds1.mnth = ds3.mnth
and ds1.p_id = ds3.p_id
and ds1.a_br = ds3.a_br
and ds1.d_br = ds3.d_br
and ds1.b_br = ds3.b_br
and ds1.dr = ds3.dr
left join dataset ds4
on ds1.tp_n = ds4.tp_n +3
and ds1.dt = ds4.dt
and ds1.mnth = ds4.mnth
and ds1.p_id = ds4.p_id
and ds1.a_br = ds4.a_br
and ds1.d_br = ds4.d_br
and ds1.b_br = ds4.b_br
and ds1.dr = ds4.dr
order by 7;

第二个使用子查询中的分区:

select sub.dt
,sub.mnth
,sub.p_id
,sub.a_br
,sub.d_br
,sub.b_br
,sub.tp_n
,sub.dr
,sub.o_m
,sub.o_n
,case when o_m2 = 0 and o_m3 = 0 and o_m4 = 0 and o_n2 in ('OD03','OT03','MO03') and o_n4 in ('OD03','OT03','MO03') and o_n4 in ('OD03','OT03','MO03') then sub.o_m
else 0 end as TO_COMPUTE
from
(
select ds.dt
,ds.mnth
,ds.p_id
,ds.a_br
,ds.d_br
,ds.b_br
,ds.tp_n
,ds.dr
,ds.o_m
,ds.o_n
,max(ds.o_m) over (partition by ds.dt, ds.mnth, ds.p_id, ds.a_br, ds.d_br, ds.b_br, ds.dr order by ds.tp_n rows between 1 preceding and 1 preceding) as O_M2
,max(ds.o_m) over (partition by ds.dt, ds.mnth, ds.p_id, ds.a_br, ds.d_br, ds.b_br, ds.dr order by ds.tp_n rows between 2 preceding and 2 preceding) as O_M3
,max(ds.o_m) over (partition by ds.dt, ds.mnth, ds.p_id, ds.a_br, ds.d_br, ds.b_br, ds.dr order by ds.tp_n rows between 3 preceding and 3 preceding) as O_M4
,max(ds.o_n) over (partition by ds.dt, ds.mnth, ds.p_id, ds.a_br, ds.d_br, ds.b_br, ds.dr order by ds.tp_n rows between 1 preceding and 1 preceding) as O_N2
,max(ds.o_n) over (partition by ds.dt, ds.mnth, ds.p_id, ds.a_br, ds.d_br, ds.b_br, ds.dr order by ds.tp_n rows between 2 preceding and 2 preceding) as O_N3
,max(ds.o_n) over (partition by ds.dt, ds.mnth, ds.p_id, ds.a_br, ds.d_br, ds.b_br, ds.dr order by ds.tp_n rows between 3 preceding and 3 preceding) as O_N4
from dataset ds
) sub
order by 7;