Question

查询我在代码中使用的内容

SET @a:=-1;

SET @b:=0;

SELECT m.allocationid,
       mt.catid,
       mt.catsname,
       r.officername,
       r.desgname,
       r.grade,
       r.cellno,
       IF(mt.catsname = 'E', @a := @a + 2,
       IF(mt.catsname = 'D', 0, @b := @b + 2)) AS
       rwid
FROM   msttransaction m,
       msttemp mt,
       regusers r
WHERE  ( m.ispending = 'Y'
         AND m.statusr = 'Approve'
         AND m.iscancelled = 'No'
         AND m.allocationid IN (SELECT mt.allocationid
                                FROM   msttemp
                                WHERE  mt.quarterid = '082505012')
         AND Substring(m.allocationid, 1, 11) = r.pfnpsno )
        OR ( m.ispending = 'N'
             AND m.type = 'Transit'
             AND m.statusr = 'Approve'
             AND m.iscancelled = 'No'
             AND m.allocationid IN (SELECT mt.allocationid
                                    FROM   msttemp
                                    WHERE  mt.quarterid = '082505012')
             AND Substring(m.allocationid, 1, 11) = r.pfnpsno )
ORDER  BY rwid,
          Substring(m.allocationid, 14)

此查询将输出显示为

SUBSTRING(m.AllocationId,-14) CatID  CatSName OfficerName        rwid
20160812000000                  4     D       TARUN DANDOTIYA     0
20160911114106                  4     D       Rahul N Chauhan     0
20180601000000                  5     E       ARUN  KUMAR         7
20170403000000                  6     F       VEERSINGH MEENA     2
20160503000000                  5     E       HEMANT  JINDAL      1
20170529000000                  6     F       AJAY RAJ            6
20161227000000                  5     E       G M SRINIVASAN      3
20170526000000                  6     F       S M KELKAR          4
20180621000000                  5     E       JANYU  JINESH       9
20170704000000                  6     F       AJAY SINGH          8
20180504000000                  5     E       GANESH  LONARE      5
20170914000000                  6     F       UMANG DUBEY         10

但是我希望我的结果为

SUBSTRING(m.AllocationId,-14) CatID  CatSName OfficerName        rwid
20160911114106                  4     D       Rahul N Chauhan     0
20160812000000                  4     D       TARUN DANDOTIYA     0
20160503000000                  5     E       HEMANT  JINDAL      1
20170403000000                  6     F       VEERSINGH MEENA     2
20161227000000                  5     E       G M SRINIVASAN      3
20170526000000                  6     F       S M KELKAR          4
20180504000000                  5     E       GANESH  LONARE      5
20170529000000                  6     F       AJAY RAJ            6
20180601000000                  5     E       ARUN  KUMAR         7
20170704000000                  6     F       AJAY SINGH          8
20180621000000                  5     E       JANYU  JINESH       9
20170914000000                  6     F       UMANG DUBEY         10

注意，这里我没有在表输出中显示

我想按日期排列输出，即在我的案例中，SUBSTRING（m.AllocationId，-14）在类别中，这意味着对于D类别，首先出现在类别中，首先是你们希望您能理解的类别，谢谢

Answer 1

您可以按类别然后按日期排序：

"query": "SELECT * " +
"FROM (SELECT hits.page.pagePath " +
"FROM " +
"[project:dataset.ga_sessions_20181015] " +
"WHERE " +
"REGEXP_MATCH( hits.page.pagePath, r'\?email=.*@.*\.*')), " +
"(SELECT " +
"hits.eventInfo.eventLabel "+
"FROM " +
"[project:dataset.ga_sessions_20181015] " +
"WHERE " +
" hits.eventInfo.eventAction = 'end-client,role,decision')"

我想按类别从早到晚排列我的记录日期

1 个答案: