Question

请说明程序的执行方式，以及为什么会生成此类特定输出。

输出为

6 10 20
6 10 8
2 2 14

我的猜测可能是由于IN，OUT，INOUT参数引起的，但我并不是很了解

#include <iostream>

using namespace std;

void sunny(int&, int);
void cloudy(int, int&);

int temp;

int main()
{
    int num1 = 6;
    int num2 = 10;
    temp = 20;

    cout << num1 << " " << num2 << " " << temp << endl;

    sunny(num1, num2);
    cout << num1 << " " << num2 << " " << temp << endl;

    cloudy(num1, num2);
    cout << num1 << " " << num2 << " " << temp << endl;
}

void sunny(int& a, int b)
{
    int w;
    temp = (a + b) / 2;
    w = a / temp;
    b = a + w;
    a = temp - b;
}

void cloudy(int u, int& v)
{
    temp = 2 * u + v;
    v = u;
    u = v - temp;
}

Answer 1

实际上输出是：

temp = (6 + 10)/2 = 8
w = 6/8 = 0 //This is because w is declared int, and int(6/8) = 0
b = 6 + 0 = 10
a = 8 - 6 = 2

我们可以看到以下步骤：

晴朗电话：

temp = 2 * 2 + 10 = 14
v = 2
u = 2 - 14 = -12 //This variable is doing nothing

因此，由于引用参数的原因，num1现在为2，并且由于其全局变量temp更改为8

多云通话：

 isError$: Observable<boolean>;

  ngOnInit() {
    this.isError$ = this.store$.select(
      ShipmentLookupStoreSelectors.selectShipmentLookupError
    );
  }

因此num2现在为2，原因与以前相同，而temp为14

IN，OUT，INOUT参数

1 个答案: