Question

花了很长时间来解决这个有关填充井字游戏棋盘的相对简单的问题。

# List variable ticTacToe should eventually 
# hold [ [ a, b, c ], [ d, e, f ], [ g, h, i ]]
# to represent the Tic Tac to board:
#    a b c
#    d e f
#    g h i

ticTacToe = [ [], [], [] ]

firstRow = input()

secondRow = input()

thirdRow = input()

ticTacToe.append(firstRow)

ticTacToe.append(secondRow)

ticTacToe.append(thirdRow)    

#Output handled for you

for i in range(3) : for j in range(3) : print( "%3s" % ticTacToe[i][j], end="") print()

输出已提供给我，无法替换。

我在这里有两个问题。

如果不删除方括号并重新开始，就无法获得[]中的行。如果要打印ticTacToe，我会得到[[], [], [], 'a,b,c', 'd,e,f', 'g,h,i']而不是[[a,b,c], [d,e,f], [g,h,i]]
不需要的引号不断出现。如果first row = a,b,c，当我将其附加到ticTacToe中时，它将显示为['a,b,c']而不是[a,b,c]

不确定我要去哪里出错，我们将不胜感激。谢谢。

Answer 1

您应该阅读有关列表的信息：PyTut lists

board = [ [], [], [] ]       # a list of 3 other lists

# addd somthing to board:    
board.append("something")    # now its a list of 3 lists and 1 string
print(board)

board = board + ["otherthing"]   # now its a list of 3 lists and 2 strings
print(board)


# modify the list inside board on place 0:
zero_innerlist = board[0]        # get the list at pos 0 of board
print(board)          
zero_innerlist.append("cat")     # put something into that inner list
print(board)
zero_innerlist.append("dog")     # put more into that inner list
print(board)
print(zero_innerlist)            # print "just" the inner list

one_innerlist = board[1]         # modify the 2nd inner list at pos 1
one_innerlist.append("demo")
print(board)

输出：

[[], [], [], 'something', 'otherthing']                     # board
[[], [], [], 'something', 'otherthing']                     # board
[['cat'], [], [], 'something', 'otherthing']                # board
[['cat', 'dog'], [], [], 'something', 'otherthing']         # board
['cat', 'dog']                                              # zero_innerlist
[['cat', 'dog'], ['demo'], [], 'something', 'otherthing']   # board

如果要将3个内容添加到每个内部列表中，则需要将3个追加添加到每个内部列表中。

其他不错的读物：string formatting和f-strings：

您正在使用2.7样式的打印，适用于3和3.6格式，并且f字符串更好：

board = [ ["a","b","c"], ["d","e","f"], ["g","h","i"] ]

for i in range(3) :
    for j in range(3) :
        print( f"{board[i][j]:3s}", end="")
    print()

# or 

for row in board:
    for col in row:
        print( f"{col:3s}", end="")
    print()

# or 

for row in board:
    print( f"{row[0]:3s}{row[1]:3s}{row[2]:3s}")

# or 

print( '\n'.join( ( ''.join(f"{col:3s}" for col in row ) for row in board) ))

输出（全部）：

a  b  c  
d  e  f  
g  h  i

Answer 2

您可以使用一个简单的循环遍历输入，并在ticTacToe列表中追加：

ticTacToe = []
for x in input('Enter rows (each element separated by comma) separated by space: ').split():
    ticTacToe.append(x.split(','))

print(ticTacToe)
#Output handled for you

样品运行：

Enter rows (each element separated by comma) separated by space: a,b,c d,e,f g,h,i
[['a', 'b', 'c'], ['d', 'e', 'f'], ['g', 'h', 'i']]

或者，将全部内容放在一行中：

ticTacToe = [x.split(',') for x in input('Enter rows (each element separated by comma) separated by space: ').split()]

Answer 3

首先，在python中，引号表示一个字符串，因此您必须将其放在其中。

由于ticTacToe是列表列表，因此您要将输入附加到最外面的列表。要附加到内部列表中：

ticTacToe = [ [], [], [] ]

firstRow = input()
secondRow = input()
thirdRow = input()

ticTacToe[0].append(firstRow)
ticTacToe[1].append(secondRow)
ticTacToe[2].append(thirdRow)  

# ticTacToe >>> [['a,b,c'], ['d,e,f'], ['g,h,i']]

但是，从输出代码开始，看来这不是您的老师想要您做的。

相反，每个列表都需要包含一个字符，而不是整个字符串。

它看起来像这样：

[['a', 'b', 'c'], ['d', 'e', 'f'], ['g', 'h', 'i']]

有很多方法可以做到这一点，但这是其中一种：

ticTacToe = [[], [], []]

firstRow = input()
secondRow = input()
thirdRow = input()

ticTacToe[0] = firstRow.split(",")
ticTacToe[1] = secondRow.split(",")
ticTacToe[2] = thirdRow.split(",")

split方法采用字符串并将其转换为提供定界符（在这种情况下为','）的列表。然后将其分配（而不是追加）到内部列表。（注意：如果在逗号后加一个空格，这是行不通的，但是我会让您知道）。

在Python中填充字符串数组-初学者CS作业问题

3 个答案: