Question

我当前正在使用以下代码从数据库中获取销售数据。它的问题在于，在没有销售的那些小时中，它不会显示0。我不介意对小时进行硬编码，但是我找不到找到这种方法的方法。因此，

1.st问题：我如何修改下面的代码以在0小时内没有销售的情况下显示0，

2.nd问题：如何从中获得有序列表。下面的代码会将9:00-10:00放置在列表的末尾，因为它不是两位数。

-- HOUR BASED SALES
select (CAST(DATEPART(HOUR, INSERTDATE) as varchar(255)) + ':00 -' +
        CAST(DATEPART(HOUR, INSERTDATE) as varchar(255)) + ':59'
       ) as [time],
       SUM (TOTAL) as REVENUE,
       COUNT (RECEIPTID) AS TOTAL_SALES,
       DEPOTID
From INVOICE INV
WHERE DEPOTID IN (25) AND TRANSDATE BETWEEN '20181025' AND '20181025'
Group By cast(datepart(hour, INSERTDATE) AS VARCHAR(255)), DEPOTID
ORDER BY CAST(DATEPART(HOUR, INSERTDATE) AS VARCHAR(255))

Answer 1

您可以列出小时数并使用left join：

select (cast(v.hh as varchar(255)) + ':00 -' +
        cast(v.hh as varchar(255)) + ':59'
       ) as [time],
       sum(TOTAL) as REVENUE,
       sum(RECEIPTID) AS TOTAL_SALES,
       depot
From (values (0), (1), . . . (23)
     ) v(hh) left join
     invoice i
     on datepart(hour, i.insertdate) = v.hh and
        i.depotid in (25) and
        i.transdate between '20181025' and '20181025'
group by v.hh, DEPOTID
order by v.hh

TSQL：获取每小时的销售数据

1 个答案: