Question

我有2个表（employee，Job）

Employee Table
Emp_no   Nationality_id  Job_Code  
1          966            99
2          996            89
3          258            10
4          123            10
5          123            20
6          987            10

工作表

Job_Code    Job_Category
99          Finance
89          Finance
10          HR
20          IT

我需要结果：
1-根据job_category中的nationalid_id = 966将所有员工计为Count1

2-根据job_category的国籍ID <> 966将所有员工计数为Count2

想要的结果是这样的

Job_Category    Count 1 Count 2
Finance           2       0
HR                0       3
IT                0       1

谢谢

很棒

我还需要将结果1和2加到

餐桌工资

Emp_id     Salary
1          1000
2          3000
3          1500

1-根据job_category（国籍ID = 966的工作类别）将所有员工的薪金加起来为sum_1

2-根据job_category的国籍ID <> 966将所有员工的薪水加起来为sum_2

最终结果是

Job_Category    Count 1 Count 2  Sum1   Sum 2
Finance           2       0      4000    0
HR                0       3      0       1500
IT                0       1      0       0

Answer 1

这应该为您做到：

WITH groups as (

    Select 

    CASE WHEN nationality_id = 966 then Count1
    Else Count2 END as count_group,
    Emp_no

    from employees

)

Select 

j.Job_Category as Job_Category,
CASE WHEN (g.count_group = Count1) then COUNT(distinct e.Emp_no)
ELSE 0 END as Count1,
CASE WHEN (g.count_group = Count2) then COUNT(distinct e.Emp_no)
ELSE 0 END as Count2

FROM employees as e

LEFT JOIN groups g on e.Emp_no = g.Emp_no 
LEFT JOIN Jobs j on e.Job_Code = j.Job_Code

Answer 2

这是条件聚合。唯一真正的把戏是salary的外部联接。

select j.job_category,
       sum(case when e.nationality = 966 then 1 else 0 end) as cnt_966,
       sum(case when e.nationality = 966 then 0 else 1 end) as cnt_other,
       sum(case when e.nationality = 966 then s.salary else 0 end) as salary_966,
       sum(case when e.nationality = 966 then 0 else s.salary end) as salary_other,
from employees e join
     jobs j
     on e.job_code = j.job_code left join
     salary s
     on s.emp_no = e.emp_no
group by j.job_category;

计算每个类别中的员工数（两个表）

2 个答案: