Question

我正在使用puppeeteer抓取网站，并显示以下代码

scrapeMoviesGeneric({
  URL: "https://villagecinemas.com.au/events/indian-cinema",
  elementPath: "ul.slider-list li.theme div.movie-name"
});


function scrapeMoviesGeneric({ URL, elementPath }) {
  console.log(elementPath);
  puppeteer.launch().then(async browser => {
    const page = await browser.newPage();
    await page.goto(URL);
    const title = await page.title();
    console.log(title);
    const movies = await page.evaluate(() =>
      Array.from(document.querySelectorAll(elementPath)).map(movie =>
        movie.innerText.trim()
      )
    );
    console.log(`movies ${movies}`);
    await browser.close();
  });
}

我收到以下错误消息

Cinemas | Where Movies Mean More

(node:6456) UnhandledPromiseRejectionWarning: Error: Evaluation failed: ReferenceError: ep is not defined
    at __puppeteer_evaluation_script__:1:42
    at ExecutionContext.evaluateHandle (C:\dev\sandbox\movie-scraper\node_modules\puppeteer\lib\ExecutionContext.js:106:13)
    at <anonymous>
    at process._tickCallback (internal/process/next_tick.js:188:7)
  -- ASYNC --
    at ExecutionContext.<anonymous> (C:\dev\sandbox\movie-scraper\node_modules\puppeteer\lib\helper.js:144:27)
    at ExecutionContext.evaluate (C:\dev\sandbox\movie-scraper\node_modules\puppeteer\lib\ExecutionContext.js:58:31)
    at ExecutionContext.<anonymous> (C:\dev\sandbox\movie-scraper\node_modules\puppeteer\lib\helper.js:145:23)
    at Frame.evaluate (C:\dev\sandbox\movie-scraper\node_modules\puppeteer\lib\FrameManager.js:439:20)

看来我的论据 elementPath 不能被document.querySelectorAll识别。

范围可见性有问题吗？

document.querySelectorAll（）不会将变量识别为参数

0 个答案: