如何使用PHP变量读取sqlite3上的数据？

Question

$result = $vt->prepare('SELECT * FROM streamdetails WHERE idFile ='.$idFile.' AND iStreamType =0');
$result->execute();
foreach($result as $row)
    echo "Çözünürlük: ".$row['iVideoWidth'] . " x " .$row['iVideoHeight'] . "<br>";
}

怎么了？

$ idFile变量类型为文本，而idFile为streamdetails上的整数。