当我在stargazer
中生成表格并省略固定效果时,然后指定omit.labels
选项,则stargazer(版本5.2.2)对每一列均显示“否”。这是一个示例:
library(stargazer)
# generate example data
set.seed(1)
list_of_states <- rep(c(1, 2, 3, 4, 5), 5)
df <- data.frame("state" = list_of_states, "y" = runif(25),
"x1" = runif(25), "x2" = runif(25))
# OLS without fixed effects
ols.1 <- glm(y ~ x1, data = df)
ols.2 <- glm(y ~ x1 + x2, data = df)
# OLS with fixed effects
fe.1 <- glm(y ~ x1 + factor(state), data = df)
fe.2 <- glm(y ~ x1 + x2 + factor(state), data = df)
stargazer(ols.1, ols.2, fe.1, fe.2,
type = "text",
align = TRUE,
omit = c("state"),
omit.labels = c("State FE"))
此输出
==================================================
Dependent variable:
--------------------------------
y
(1) (2) (3) (4)
--------------------------------------------------
x1 0.088 0.098 0.151 0.157
(0.241) (0.264) (0.263) (0.283)
x2 0.028 0.022
(0.270) (0.287)
Constant 0.485*** 0.467* 0.466** 0.452
(0.142) (0.227) (0.215) (0.280)
--------------------------------------------------
State FE No No No No
--------------------------------------------------
Observations 25 25 25 25
Log Likelihood -5.321 -5.315 -3.528 -3.524
Akaike Inf. Crit. 14.642 16.630 19.056 21.048
==================================================
Note: *p<0.1; **p<0.05; ***p<0.01
“状态FE”行中的标签在最后两列中应显示“是”。这是错误吗?
答案 0 :(得分:1)
简短的答案是它是一个错误。看来,该代码的目的是创建一个看起来像
的矩阵#!/usr/bin/perl
use strict;
use warnings;
use DateTime;
my @bitcounts = (
0, 1, 1, 2, 1, 2, 2, 3, 1, 2, 2, 3, 2, 3, 3, 4, 1, 2, 2, 3, 2, 3,
3, 4, 2, 3, 3, 4, 3, 4, 4, 5, 1, 2, 2, 3, 2, 3, 3, 4, 2, 3, 3, 4,
3, 4, 4, 5, 2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6, 1, 2,
2, 3, 2, 3, 3, 4, 2, 3, 3, 4, 3, 4, 4, 5, 2, 3, 3, 4, 3, 4, 4, 5,
3, 4, 4, 5, 4, 5, 5, 6, 2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5,
5, 6, 3, 4, 4, 5, 4, 5, 5, 6, 4, 5, 5, 6, 5, 6, 6, 7, 1, 2, 2, 3,
2, 3, 3, 4, 2, 3, 3, 4, 3, 4, 4, 5, 2, 3, 3, 4, 3, 4, 4, 5, 3, 4,
4, 5, 4, 5, 5, 6, 2, 3, 3, 4, 3, 4, 4, 5, 3, 4, 4, 5, 4, 5, 5, 6,
3, 4, 4, 5, 4, 5, 5, 6, 4, 5, 5, 6, 5, 6, 6, 7, 2, 3, 3, 4, 3, 4,
4, 5, 3, 4, 4, 5, 4, 5, 5, 6, 3, 4, 4, 5, 4, 5, 5, 6, 4, 5, 5, 6,
5, 6, 6, 7, 3, 4, 4, 5, 4, 5, 5, 6, 4, 5, 5, 6, 5, 6, 6, 7, 4, 5,
5, 6, 5, 6, 6, 7, 5, 6, 6, 7, 6, 7, 7, 8
);
for (my $i=0; $i <= 10; $i++) {
system("dd if=/dev/hwrng of=temprnd.bin bs=25 count=1 status=none");
my $filename = 'temprnd.bin';
open(my $fh, '<', $filename) or die "$!";
binmode $fh;
my $count = 0;
my $byte = 0;
while ( read $fh, $byte, 1 ) {
$count += $bitcounts[ord($byte)];
}
my $dt = DateTime->now;
print join ',', $dt->ymd, $dt->hms,"$count\n";
system("rm temprnd.bin");
sleep 1;
}
__END__
,然后检查cbind(names(coef(ols.1)), names(coef(fe.1)))
# [,1] [,2]
# [1,] "(Intercept)" "(Intercept)"
# [2,] "x1" "x1"
# [3,] "(Intercept)" "factor(state)2"
# [4,] "x1" "factor(state)3"
# [5,] "(Intercept)" "factor(state)4"
# [6,] "x1" "factor(state)5"
正则表达式的每一列。但是,实际发生的情况是
omit
,导致找不到cbind(cbind(NULL, names(coef(ols.1))), names(coef(fe.1)))
# [,1] [,2]
# [1,] "(Intercept)" "(Intercept)"
# [2,] "x1" "x1"
字词。发生这种情况是因为,从omit
当参数由矩阵和向量的混合组成时,结果的列(行)数由矩阵参数的列(行)数确定。任何向量都会对其值进行回收或子集化以达到此长度。