设置线程链接并在home.html上创建

时间:2018-10-27 21:09:04

标签: python django slugify

我试图对我的超链接进行打点。我创建了Django面板(home.html):

目前,我有:

http://127.0.0.1:8000/request/2/

但是我想要:http://127.0.0.1:8000/request/hallo-das-ist-ein-test-9/

enter image description here

  {% for topic in topics %}
    <tr>
      <td>{{ topic.slug }}</td>
       <td><a href="{% url 'topic_posts' topic.pk %}">{{ topic.subject }}</a></td>
      <td>{{ topic.starter.username }}</td>
      <td>0</td>
      <td>0</td>
      <td>{{ topic.last_updated }}</td>
    </tr>
  {% endfor %}

class Topic(models.Model):
    subject = models.CharField(max_length=255)
    category = models.CharField(max_length=255, null=True)
    last_updated = models.DateTimeField(auto_now_add=True)
    starter = models.ForeignKey(User, on_delete=models.CASCADE, 
related_name='topics')
    slug = models.SlugField(unique=True)

def save(self, *args, **kwargs):
    self.slug = slugify(self.subject)
    super(Topic, self).save(*args, **kwargs)

您可以看到,子弹已创建。 (第一列= {{topic.slug}})

如何创建条形链接并将其链接到我的线程超链接? (例如“ hallo das ist ein test:9”)

我当前在views.py中的代码:

def home(request):
    topics = Topic.objects.all()
    return render(request, 'home.html', {'topics': topics})


def topic_posts(request, topic_pk):
    topic = get_object_or_404(Topic, pk=topic_pk)
    return render(request, 'topic_posts.html', {'topic': topic})

我当前的url.py:

urlpatterns = [
    url(r'^$', views.home, name='home'),
    url(r'^admin/', admin.site.urls),
    url(r'^new/$', views.new_topic, name='new_topic'),
    url(r'^request/(?P<topic_pk>\d+)/$', views.topic_posts, 
name='topic_posts'),
    url(r'^request/(?P<topic_pk>\d+)/reply/$', views.reply_topic, 
name='reply_topic'),

]

我已经尝试过不同的方法,例如:

def home(request):
    topics = Topic.objects.all()
    slug = Topic.slug
    return render(request, 'home.html', {'topics': topics, 'slug': slug})


def topic_posts(request, slug):
    slug = get_object_or_404(Topic, pk=slug)
    return render(request, 'topic_posts.html', {'slug': slug})

home.html:

<td><a href="{% url 'topic_posts' topic.slug %}">{{ topic.subject }}</a></td>

url.py:

urlpatterns = [
    url(r'^$', views.home, name='home'),
    url(r'^admin/', admin.site.urls),
    url(r'^new/$', views.new_topic, name='new_topic'),
    url(r'^request/(?P<slug>[-\w\d]+)/$', views.topic_posts, 
 name='topic_posts'),
    url(r'^request/(?P<topic_pk>\d+)/reply/$', views.reply_topic, 
 name='reply_topic'),
]

我在这里做错了什么...?

1 个答案:

答案 0 :(得分:0)

您的预期行为需要进行一些更改。

在表更改中:

  <a href="{% url 'topic_posts' topic.pk %}">

 <a href="{% url 'topic_posts' slug=topic.slug %}">

在视图中,像这样更新代码:

def topic_posts(request, slug):
    topic = get_object_or_404(Topic, slug=slug)
    ...