在PHP7中如何将thes代码从preg_replace（）替换为preg_replace_callback（）

Question

如何将这些代码从preg_replace（）替换为preg_replace_callback（）？

$search_array   =   array();
$replace_array  =   array();

$search_array[]     =   '~\{\$([^[<].*?)\[\'([^[<].*?)\'\]\[\'([^[<].*?)\'\]\}~';
$replace_array[]    =   '<?php echo $DHGS->_CONF[\'template\'][\'\\1\'][\'\\2\'][\'\\3\']; ?>';

$search_array[]     =   '~\{\$([^[<].*?)\[([^[<].*?)\]\[([^[<].*?)\]\}~';
$replace_array[]    =   '<?php echo $DHGS->_CONF[\'template\'][\'\\1\'][\'\\2\'][\'\\3\']; ?>';

$search_array[]     =   '~\{\$([^[<].*?)\[\'([^[<].*?)\'\]\}~';
$replace_array[]    =   '<?php echo $DHGS->_CONF[\'template\'][\'\\1\'][\'\\2\']; ?>';

$search_array[]     =   '~\{\$([^[<].*?)\[([^[<].*?)\]\}~';
$replace_array[]    =   '<?php echo $DHGS->_CONF[\'template\'][\'\\1\'][\'\\2\']; ?>';

$search_array[]     =   '~\{\$([^[<].*?)\}~';
$replace_array[]    =   '<?php echo $DHGS->_CONF[\'template\'][\'\\1\']; ?>';

$search_array[]     =   '~\{template}([^[<].*?){/template}~';
$replace_array[]    =   '<?php $this->display(\'\\1\'); ?>';

$search_array[]     =   '~\{include}([^[<].*?){/include}~';
$replace_array[]    =   '<?php include(\\1); ?>';

$search_array[]     =   '~\{info_row}([^[<].*?){/info_row}~';
$replace_array[]    =   '<?php $this->info_row(\'\\1\'); ?>';

$search_array[]     =   '~\{get_hook}([^[<].*?){/get_hook}~';
$replace_array[]    =   '<?php $this->get_hooks_template(\'\\1\'); ?>';

//////////
$string = preg_replace($search_array,$replace_array,$string);

上面的代码给出了不建议使用的警告。

如何从preg_replace转换为preg_replace_callback！ 我尝试进行转换，但这是一个复杂的过程..