我很难在C中使用命名管道来实现两项任务:
我已经做过单一生产者-单一消费者的问题,但是我不确定如何开始解决上述任务,您能通过建议合适的方法和方法来向我提出建议吗?
这是我的单一生产者-单一消耗者代码:
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <fcntl.h>
#include <sys/types.h>
#include <sys/stat.h>
#include <sys/wait.h>
const int dataAmountToProduce = 10;
int value = 0;
int const buforSize = 50;
void processProducer()
{
int savePipe;
while (value < dataAmountToProduce)
{
savePipe = open("pipe", O_WRONLY);
value++;
char str[buforSize];
sprintf(str, "%d", value);
printf("Producer %d produces value: %s\n", getpid(), str);
write(savePipe, str, buforSize);
if (value == dataAmountToProduce)
{
break;
}
}
close(savePipe);
}
void processConsumer()
{
int readPipe;
while (value < dataAmountToProduce)
{
readPipe = open("pipe", O_RDONLY);
char buf[buforSize];
read(readPipe, buf, buforSize);
printf("Consumer %d consumes value: %s\n", getpid(), buf);
value = atoi(buf);
if (value == dataAmountToProduce)
{
break;
}
}
close(readPipe);
}
main()
{
mkfifo("pipe", 0600);
if (fork() == 0)
{
printf("Creating producer process %d\n", getpid());
processProducer();
printf("Producer process %d finished work\n", getpid());
exit(0);
}
if (fork() == 0)
{
printf("Creating consumer process %d\n", getpid());
processConsumer();
printf("Consumer process %d finished work\n", getpid());
exit(0);
}
wait(NULL);
printf("Both child processes of process %d finished work.\n", getpid());
exit(0);
}
答案 0 :(得分:0)
好的,在这两种情况下,我自己都找到了解决方案,我将此代码块添加到了生产者方法:
if (value == valuesAmountToProduce)
{
printf("Producent process %d sent END signal\n", getpid());
for (int i = 0; i <= amountOfConsumers; i++)
{
write(savePipe, "END", wielkoscBufora);
}
在使用者代码中,我正在检查传递的值是否为END,如果是,那么我正在打破循环:
if (strcmp(buf, "END") == 0)
{
printf("Consumer process %d recived END signal\n", getpid());
break;
}
我以这种方式解决了我的问题,对于多个生产者-单个使用者,我们可以忽略使用者循环,因为它只有第一个代码片段,因为它只有第一个使用者。