Question

我想返回一个仅包含原始字符串数组值的第一个字母的数组。

例如：假设我有以下数组：

var array = ["gsss", "osgs", "ortr", "dges"];

并且我需要一些函数来返回这个：

["g", "o", "o", "d"]

Answer 1

您可以使用map()遍历数组。通过o[0]

获取字符串的第一个字母

var array = ["gsss", "osgs", "ortr", "dges"];
var result = array.map(o => o[0]);

console.log(result);

Answer 2

您可以使用forEach和charAt来完成

var array = ["gsss", "osgs", "ortr", "dges"];
var result = new Array();
array.forEach(v =>{
  result.push(v.charAt(0));
});
   console.log(result);

Answer 3

使用t = threading.Thread(target=c.run,args=(10,), daemon=True)

map()

Answer 4

一种方法是：

// on the grounds that you may want to repeat the
// functionality but for a different index, we use
// compose a named function that takes two arguments.
// haystack: Array of strings from which you wish to
// retrieve the characters;
// index: (optional, defaults to 0), specifies the
// index from which you wish to retrieve the characters:
let charsAtNFrom = (haystack, index = 0) => {

    //  here we iterate over the Array using
    // Array.prototype.map(), with an Arrow function:
    return haystack.map(
      // 'str' represents the current String of the Array
      // of Strings over which we're iterating; and we return
      // the character at the specified index:
      (str) => str.charAt(index)
    );
  },
  stringArray = ["gsss", "osgs", "ortr", "dges"],
  firstLetters = charsAtNFrom(stringArray);

console.log(firstLetters);

参考文献：

Answer 5

使用Array Reduce返回一个新数组：

let arr = ["gsss", "osgs", "ortr", "dges"];
let newArray = arr.reduce((newArr, curVal)=>{
    return newArr.push(curVal.charAt(0));
}, []);

Answer 6

String[] array = new String[]{"gsss", "osgs", "ortr", "dges"};

        char array1[] = new char[array.length]; //creating another Character Array

        for(int i = 0;i<array.length;i++) { //taking first character for each element of the Array
        array1[i]= array[i].charAt(0);  
        }

编辑字符串数组，仅保留值中的第一个字母

6 个答案: