Question

Ajax脚本

<script>
function tankdip(str) {
    if (str == "") {
        document.getElementById("open").innerHTML = "";
        return;
    } else { 
    var num = parseFloat(str);
        var tank = document.getElementById("pumps"+count).value;

        if (window.XMLHttpRequest) {
            // code for IE7+, Firefox, Chrome, Opera, Safari
            xmlhttp = new XMLHttpRequest();
        } else {
            // code for IE6, IE5
            xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
        }
        xmlhttp.onreadystatechange = function() {
            if (this.readyState == 4 && this.status == 200) {
                document.getElementById("open").innerHTML = this.responseText;
            }
        };
        xmlhttp.open("GET","open.php?open="+num+"&tank="+tank,true);
        xmlhttp.send();
    }
}
</script>

HTML表格

<td><input type="text" name="odip[]"   id="odip" data-srno="1" class="form-control input-sm " onkeyup="tankdip(this.value)" required></td>
<td><select  name="open[]"  id="open" data-srno="1" class="form-control input-sm " readonly></select></td>

open.php

<?php
include "connect.php";
$con=mysqli_connect("$host", "$username", "$password","$db_name")or die("Your Connection is in error");
$open = $_GET['open'];
$tank    = $_GET['tank'];
$sql     = mysqli_query($con,"SELECT dip,cap from $tank where dip = '$open'");
while ($row = mysqli_fetch_array($sql))
{
$combo.="<option >" . $row[1]. "</option>";
}

echo $combo;

?>

我想使用ajax获取对应的“ odip”值的“ open”值。但是当我尝试发送float（12.34）时就变成（12）。我希望日期以Float发送。

Answer 1

尝试

function tankdip(str) {
  console.log("Input str:", str);

您确定str是浮动的吗？

也可能是某些表中的dip字段具有INT类型吗？

php-Ajax：发送Float数据并获取响应

1 个答案: