如何使用Noje JS在续集中获取数据

时间:2018-10-27 09:29:09

标签: node.js sequelize.js sequelize-cli

这是我使用的代码,已提取数据库中的所有数据,但我没有获得价值。我是新来的续集。

   Project.findAll({ raw: true}).then(function (users) {
        console.log(users);
  console.log(users.dataValues);

    }).catch(function (err) {
        console.log('Oops! something went wrong, : ', err);
    });

这是输出: 这是console.log(users);

   [ DAO {
        dataValues: 
         { idProject: 1,
           projectName: 'Symfony',
           isActive: '1',
           createdAt: 2018-10-23T06:32:43.000Z,
           modifiedAt: 2018-10-23T06:32:43.000Z },
        _previousDataValues: 
         { idProject: 1,
           projectName: 'Symfony',
           isActive: '1',
           createdAt: 2018-10-23T06:32:43.000Z,
           modifiedAt: 2018-10-23T06:32:43.000Z },

        options: { isNewRecord: false, isDirty: false, raw: true },
        hasPrimaryKeys: true,
        selectedValues: 
         RowDataPacket {
           idProject: 1,
           projectName: 'Symfony',
           isActive: '1',
           createdAt: 2018-10-23T06:32:43.000Z,
           modifiedAt: 2018-10-23T06:32:43.000Z },
        __eagerlyLoadedAssociations: [],
        isNewRecord: false }.....

这是console.log(users.dataValues);

undefined

怎么可能?

1 个答案:

答案 0 :(得分:1)

使用 findAll 时,它返回一个数组,如您在文档中所见: http://docs.sequelizejs.com/class/lib/model.js~Model.html#static-method-findAll

所以您应该遍历此数组,如下所示:

 Project.findAll({ raw: true})
 .then(projects => {
    projects.forEach(project => {
       console.log(project);
       console.log('project name', project.projectName);
    })
 }).catch(function (err) {
     console.log('Oops! something went wrong: ', err);
 });

您可以选择使用Async / Await来获得更简洁的代码:

 try {
   const projects = await Project.findAll({ raw: true});
   projects.forEach(project => {
        console.log('project name ', project.projectName);
   })
 } catch(err) {
     console.log('Oops! something went wrong: ', err);
 }