Question

我正在此处发布当前遇到的问题，我有一个数组，其中必须过滤以“！”开头的值然后算了一下，我尝试了array_filter，但没有用，我想知道是否还有另一种方法来过滤值并以“！”开头的值分开我要在下面的数组中贴上代码以节省空间

这是我到目前为止完成的代码：

$dat= Array
(
    [0] => Lorem
    [1] => ipsum
    [2] => dolor
    [3] => sit
    [4] => amet,
    [5] => consectetur
    [6] => adipiscing
    [7] => elit.
    [8] => &lt;a
    [9] => class=&quot;btn
    [10] => btn-default&quot;
    [11] => href=&quot;hash_sys.php?tag=bart&quot;&gt;
    [12] => !bart
    [13] => &lt;/a&gt;
    [14] => Quisque
    [15] => sapien
    [16] => velit,
    [17] => aliquet
    [18] => eget
    [19] => commodo
    [20] => nec,

    [21] => !qwerty
    [22] => auctor
    [23] => a
    [24] => sapien.
    [25] => Nam
    [26] => eu
    [27] => neque
    [28] => vulputate
    [29] => diam
    [30] => rhoncus
    [31] => faucibus.
    [32] => Curabitur
    [33] => quis
    [34] => varius
    [35] => libero.
    [36] => &lt;a
    [37] => class=&quot;btn
    [38] => btn-default&quot;
    [39] => href=&quot;hash_sys.php?tag=qwerty&quot;&gt;
    [40] => !qwerty
    [41] => &lt;/a&gt;
    [42] => Lorem.
)
 foreach($dat as $d){
                    if(strpos($d ,'!') !== FALSE ){
                 $d_p=""; 
            $i=0;
            $tag="";
                     $d2=count($dat);
                     while ($i<$d2) {

                         $d_w=$dat[$i];

                            $regex="/!+([a-zA-z0-9._-]+)/";
                            $regex1="/(?:\s|^)![A-Za-z0-9\-\.\_]+(?:\s|$)/";
                    $d1=preg_match_all($regex, $dat[$i],$output_preg,PREG_PATTERN_ORDER);


                       function check_regex($data){
                           if ($data=="/(?:\s|^)![A-Za-z0-9\-\.\_]+(?:\s|$)/")
                           {
                               return $data;
                           }

                           }


                       $d_p= array_column($dat,$output_preg[0][0],$regex1);

                       $d_f= array_filter($d_p,"check_regex" , ARRAY_FILTER_USE_BOTH);
                   $d_c= array_count_values($d_p);
                   print_r($d_p);
                   foreach ($d_c as $d2) {
                       if ($d2>1 ) {
                           $tag=1;

                       } 
                   }
                   $i++;
                     }

                     if($tag==1){
                        echo 1;
                        exit();
                    } else {
                    echo 0;
                }    
                     }

Answer 1

我没有阅读您的代码。这样一个小问题真是太过庞大了，如果我错过了什么，请原谅我。

我使用preg_grep过滤掉前面带有!的值。
如果您随后想要不带!的所有列表，则可以使用array_diff。

$arr = ["!qwerty","sapien", "!Bart", "!qwerty"];

$filtered = preg_grep("/^\!.*$/", $arr);

var_dump($filtered);
var_dump(array_diff($arr, $filtered));

https://3v4l.org/uj4Gb

通过使用模式中的!，正则表达式模式将确保值以^ $开头，然后.*接受任何内容

Answer 2

我了解的是：

从数组中删除所有以！开头的元素。
计算已删除的元素数量

这是我的工作代码

$dat= Array("Lorem","ipsum","dolor","sit","amet,","consectetur","adipiscing","elit.","&lt;a","class=&quot;btn"," btn-default&quot;"," href=&quot;hash_sys.php?tag=bart&quot;&gt;"," !bart"," &lt;/a&gt;"," Quisque"," sapien"," velit,"," aliquet"," eget"," commodo"," nec,",
    " !qwerty"," auctor"," a"," sapien."," Nam"," eu"," neque"," vulputate"," diam"," rhoncus"," faucibus."," Curabitur"," quis"," varius"," libero."," &lt;a"," class=&quot;btn"," btn-default&quot;"," href=&quot;hash_sys.php?tag=qwerty&quot;&gt;"," !qwerty"," &lt;/a&gt;"," Lorem.",
);
$filter = array();
foreach($dat as $d){
    if(substr($d,0,1) !== "!")
        $filter[] = $d;
}
echo "<h3>Original</h3>";
echo "<pre>"; var_dump($dat); echo "</pre>";
echo "<h3>Filtered</h3>";
echo "<pre>"; var_dump($filter); echo "</pre>";
echo "<h3>Count Difference</h3>";
echo "<pre>"; var_dump(sizeof($dat) - sizeof($filter)); echo "</pre>";

substr检查我字符串的第一个元素是否为！

如果不是以！开头添加到过滤器数组中的

过滤后的元素是dat和filter的大小相减

如何过滤数组中的值

2 个答案: