Question

我正在处理电影数据库，正在从imdb获得响应。我得到的是xml格式的响应，但是它没有标签，只有信息混合了。我如何在那里获取每个数据？

以下是显示回复的方式：

contract.methods.addReview(review).send({
 from: accounts[0],
 value: SOME_AMOUNT_IN_ETH
})

Answer 1

这是我对你问题的回答

xmlRaw="""< ?xml
version = "1.0"
encoding = "UTF-8"? > < root
response = "True" >
< movie
title = "Batman"
year = "1989"
rated = "PG-13"
released = "23 Jun 1989"
runtime = "126 min"
genre = "Action, Adventure"
director = "Tim Burton"
writer = "Bob Kane (Batman characters), Sam Hamm (story), Sam Hamm (screenplay), Warren Skaaren (screenplay)"
actors = "Michael Keaton, Jack Nicholson, Kim Basinger, Robert Wuhl"
plot = "Gotham City. Crime boss Carl Grissom (Jack Palance) effectively runs the town but there's a new crime fighter in town - Batman (Michael Keaton). Grissom's right-hand man is Jack Napier (Jack Nicholson), a brutal man who is not entirely sane... After falling out between the two Grissom has Napier set up with the Police and Napier falls to his apparent death in a vat of chemicals. However, he soon reappears as The Joker and starts a reign of terror in Gotham City. Meanwhile, reporter Vicki Vale (Kim Basinger) is in the city to do an article on Batman. She soon starts a relationship with Batman's everyday persona, billionaire Bruce Wayne."
language = "English, French, Spanish"
country = "USA, UK"
awards = "Won 1 Oscar. Another 8 wins & 26 nominations."
poster = "https://m.media-amazon.com/images/M/MV5BMTYwNjAyODIyMF5BMl5BanBnXkFtZTYwNDMwMDk2._V1_SX300.jpg"
metascore = "69"
imdbRating = "7.6"
imdbVotes = "302,842"
imdbID = "tt0096895"
type = "movie" / >
< / root >"""

def getValue(xml, value):
    textString = xmlRaw.split('\n')
    for line in textString:
        if value in line:
            returnData = line
    return returnData

print (getValue(xmlRaw, 'title'))
print (getValue(xmlRaw, 'year'))
print (getValue(xmlRaw, 'rated'))
print (getValue(xmlRaw, 'released'))

#add more as you need the data

从没有标签的xml imdb响应中获取信息

1 个答案: