Question

背景

我将数据存储在字典中。词典的长度可以不同，并且在特定词典中，键可能具有多个值。我正在尝试将数据吐出到CSV文件中。

问题/解决方案

图像1是我的实际输出打印出来的方式。图2显示了我如何希望我的输出实际打印出来。 图像2是所需的输出。

代码

import csv
from itertools import izip_longest

e = {'Lebron':[25,10],'Ray':[40,15]}
c = {'Nba':5000}

def writeData():
    with open('file1.csv', mode='w') as csv_file:
        fieldnames = ['Player Name','Points','Assist','Company','Total Employes']
        writer = csv.writer(csv_file)
        writer.writerow(fieldnames)

        for employee, company in izip_longest(e.items(), c.items()):
            row = list(employee)
            row += list(company) if company is not None else ['', '']  # Write empty fields if no company

            writer.writerow(row)

writeData()

我愿意接受所有可以帮助我获得所需输出格式的解决方案/建议。

Answer 1

from collections import defaultdict

values = defaultdict(dict)
values[Name1] = {Points: [], Assist: [], Company: blah, Total_Employees: 123}

用于生成输出，遍历值中的每个项目以给您命名，然后使用嵌套字典中的key_values填充其他值。

再次，确保没有多个具有相同名称的条目，或者在defaultdict中选择一个具有唯一条目的条目。

示例演示-

>>> from collections import defaultdict
>>> import csv
>>> values = defaultdict(dict)
>>> vals = [["Lebron", 25, 10, "Nba", 5000], ["Ray", 40, 15]]
>>> fields = ["Name", "Points", "Assist", "Company", "Total Employes"]
>>> for item in vals:
...     if len(item) == len(fields):
...             details = dict()
...             for j in range(1, len(fields)):
...                     details[fields[j]] = item[j]
...             values[item[0]] = details
...     elif len(item) < len(fields):
...             details = dict()
...             for j in range(1, len(fields)):
...                     if j+1 <= len(item):
...                             details[fields[j]] = item[j]
...                     else:
...                             details[fields[j]] = ""
...             values[item[0]] = details
... 
>>> values
defaultdict(<class 'dict'>, {'Lebron': {'Points': 25, 'Assist': 10, 'Company': 'Nba', 'Total Employes': 5000}, 'Ray': {'Points': 40, 'Assist': 15, 'Company': '', 'Total Employes': ''}})
>>> csv_file =  open('file1.csv', 'w')
>>> writer = csv.writer(csv_file)
>>> for i in values:
...     row = [i]
...     for j in values[i]:
...             row.append(values[i][j])
...     writer.writerow(row)
... 
23
13
>>> csv_file.close()

“ file1.csv”的内容：

Lebron,25,10,Nba,5000
Ray,40,15,,

Answer 2

要获得更简单的答案，您只需要在现有内容中添加一行代码即可：

row = [row[0]] + row[1]

如此：

for employee, company in izip_longest(e.items(), c.items()):
        row = list(employee)
        row = [row[0]] + row[1]
        row += list(company) if company is not None else ['', '']  # Write empty fields if no company

从每个键具有多个值的字典将数据写入csv

2 个答案: