MySQLi准备好的语句失败，将不会执行

Question

我的SQL语句有问题，它在第一个if语句上给出错误，该SQL语句已失败。对于准备好的语句，我使用了mmtuts和w3schools，但我不知道出了什么问题。

这是我的代码：

function login($conn) {
  if (isset($_POST['submitLogin'])) {
    $username = $conn->escape_string($_POST['emailorusername']);
    $password = $conn->escape_string($_POST['password']);
    $sql = "SELECT * FROM users WHERE username = ?";
    $stmt = mysqli_stmt_init($conn);
    if (!mysqli_stmt_prepare($stmt, $sql)) {
      header("Location: ?error=sqlstatementfailed");
      exit();
    } else {
      mysqli_stmt_prepare($stmt, $sql);
      mysqli_stmt_bind_param($stmt, "s", $username);
      mysqli_stmt_execute($stmt);
      $result = mysqli_stmt_get_result($stmt);
      $row = mysqli_fetch_assoc($result);
      if (mysqli_num_rows($result) == 0) {
        header("Location: ?username=notfound");
        exit();
      } else {
        if (mysqli_num_rows($result) > 1) {
          header("Location: ?error=toomuchresults");
          exit();
        } else {
          header("Location: ?username=ok");
          if ($password !== $row['password']) {
            header("Location: ?password=false");
            exit();
          } else {
            header("Location: ?password=ok");
            $_SESSION['username'] = $row['username'];
            $_SESSION['email'] = $row['email'];
            $_SESSION['firstname'] = $row['firstname'];
            $_SESSION['lastname'] = $row['lastname'];
            header("Location: Index");
            exit();
          }
        }
      }
    }
  }
}

服务器已连接到数据库，所以这不是问题。

有人可以帮忙吗？谢谢！

解决方案：

准备完成后检查mysqli errors，它将告诉您失败的原因。