Question

下面我们有2个int数组来存储本国和外地的足球比赛结果...我需要显示统计数据我有多少次平局结果。有人可以帮我忙吗？我无法弄清楚。请假设这是我有史以来的第一个程序，如果您有任何解决方案，请给我注释代码..我需要向老师解释我是如何做到的。谢谢

    String[] HomeTeam = new String[10];
    String[] AwayTeam = new String[10];
    int[] HomeScore = new int[10];
    int[] AwayScore = new int[10];

    int index = 0;
    int sum = 0;
    int sum1 = 0;

    do 
    {
        System.out.print("Enter Home Team Name: ");
        HomeTeam[index] = kbd.nextLine();
        System.out.print("Enter Away Team Name: ");
        AwayTeam[index] = kbd.nextLine();
        System.out.print("Enter Home Team Score:");
        HomeScore[index] = kbd.nextInt();
        System.out.print("Enter Away Team Score: ");
        AwayScore[index] = kbd.nextInt();
        kbd.nextLine();


    } while(index < 10);
    index = 0;

    System.out.println();   

    do 
    {
        System.out.println(HomeTeam[index] + " [" + HomeScore[index] + "]" + " | " + AwayTeam[index] + " [" + AwayScore[index] + "] ");
        index = index + 1;

    } while(index < 10);

    kbd.close();

    for(index = 0; index < 10; index++)
        sum += HomeScore[index];
        for(index = 0; index < 10; index++)
            sum1 += AwayScore[index];

    System.out.println();
    System.out.println("Totals");
    System.out.println("-------------------------------");
    System.out.println("Total number of matches played: " + index);
    System.out.println("Total of all home scores: " + sum);
    System.out.println("Total of all away scores: " + sum1);
    System.out.println("Total number of draws: ");
    System.out.println("The highest home score: ");
    System.out.println("The highest away score: ");

}

}

Answer 1

为了编写代码，您必须清楚要实现的解决方案。一个好的初学者实践是编写程序执行的流程图（键盘前准备纸）。

我把它作为一个参考，以供将来参考：

因此，考虑到该算法，我实现了一个可能的解决方案（使用硬编码数据）。

MainClass：

public class MainE {

    public static void main(String[] args) {

        String[] homeTeam = { "q", "w", "e", "r", "t", "y", "u", "i", "o", "p"};
        String[] awayTeam = {"p", "o", "i", "u", "y", "t", "r", "e", "w", "q"};
        int[] homeScore = {5,1,3,5,6,1,10,4,3,2};
        int[] awayScore = {4,3,2,1,3,5,42,1,3,2};

        int sumHome = 0;
        int sumAway = 0;
        int drawCount = 0;

        int highestHomeScore = homeScore[0];
        int highestAwayScore = awayScore[0];

        System.out.println();

        for (int index = 0; index < 10; index++) {

            System.out.println(homeTeam[index] + " [" + homeScore[index] + "]"
                    + " | " + awayTeam[index] + " [" + awayScore[index] + "] ");
            sumHome += homeScore[index];
            sumAway += awayScore[index];

            if (homeScore[index] > highestHomeScore) highestHomeScore = homeScore[index];
            if (awayScore[index] > highestAwayScore) highestAwayScore = awayScore[index];

            if(homeScore[index] == awayScore[index]) drawCount++;
        }



        System.out.println();
        System.out.println("Totals");
        System.out.println("-------------------------------");
        System.out.println("Total number of matches played: " + homeTeam.length);
        System.out.println("Total of all home scores: " + sumHome);
        System.out.println("Total of all away scores: " + sumAway);
        System.out.println("Total number of draws: " + drawCount);
        System.out.println("The highest home score: " + highestHomeScore);
        System.out.println("The highest away score: " + highestAwayScore);

    }

}

输出：

q [5] | p [4] 
w [1] | o [3] 
e [3] | i [2] 
r [5] | u [1] 
t [6] | y [3] 
y [1] | t [5] 
u [10] | r [42] 
i [4] | e [1] 
o [3] | w [3] 
p [2] | q [2] 

Totals
-------------------------------
Total number of matches played: 10
Total of all home scores: 40
Total of all away scores: 66
Total number of draws: 2
The highest home score: 10
The highest away score: 42

编辑：

如果要避免使用空值，则必须询问每次迭代if(homeTeam[index] != null )，也要手动计算匹配项（不再匹配数组长度）

处理空值

public class MainE {

    public static void main(String[] args) {

        String[] homeTeam = { "q", "w", "e", null, "t", "y", "u", "i", "o", "p"};
        String[] awayTeam = {"p", "o", "i", null, "y", "t", "r", "e", "w", "q"};
        int[] homeScore = {5,1,3,0,6,1,10,4,3,2};
        int[] awayScore = {4,3,2,0,3,5,42,1,3,2};

        int sumHome = 0;
        int sumAway = 0;
        int drawCount = 0;
        int matches = 0;

        int highestHomeScore = homeScore[0];
        int highestAwayScore = awayScore[0];

        System.out.println();

        for (int index = 0; index < 10; index++) {
            if(homeTeam[index] != null ){
                System.out.println(homeTeam[index] + " [" + homeScore[index] + "]"
                        + " | " + awayTeam[index] + " [" + awayScore[index] + "] ");
                sumHome += homeScore[index];
                sumAway += awayScore[index];

                if (homeScore[index] > highestHomeScore) highestHomeScore = homeScore[index];
                if (awayScore[index] > highestAwayScore) highestAwayScore = awayScore[index];

                if(homeScore[index] == awayScore[index]) drawCount++;
                matches++;
            }


        }



        System.out.println();
        System.out.println("Totals");
        System.out.println("-------------------------------");
        System.out.println("Total number of matches played: " + matches);
        System.out.println("Total of all home scores: " + sumHome);
        System.out.println("Total of all away scores: " + sumAway);
        System.out.println("Total number of draws: " + drawCount);
        System.out.println("The highest home score: " + highestHomeScore);
        System.out.println("The highest away score: " + highestAwayScore);

    }

}

输出：

q [5] | p [4] 
w [1] | o [3] 
e [3] | i [2] 
t [6] | y [3] 
y [1] | t [5] 
u [10] | r [42] 
i [4] | e [1] 
o [3] | w [3] 
p [2] | q [2] 

Totals
-------------------------------
Total number of matches played: 9
Total of all home scores: 35
Total of all away scores: 65
Total number of draws: 2
The highest home score: 10
The highest away score: 42

注意：一个更好的选择是在询问输入时跳过空值。

Answer 2

添加另一个名为drawCount的局部变量。遍历得分数组，并检查两个数组在循环索引处的元素是否相等。如果是这样，则将drawCount加1。然后在最后打印。

此外，您可以将For循环合并为一个循环。

Answer 3

您的代码中有2个for循环，但是只需要1就可以得到所需的所有结果，因为所有数组的大小均为10。
因此，在此循环中：

for(index = 0; index < 10; index++) {
   // calculations
}

通过在所有数组中使用index来计算Home和Away的所有总和，平局次数和最高分数。
另一个建议：对变量使用更易读的名称，例如：
sumMatches，sumHomeScore，sumAwayScore，sumDraws，sumHighestHome，sumHighestAway。

如何查看我有多少个抽奖结果并显示？

3 个答案:

MainClass：

输出：

处理空值

输出：