我有一个表名 tbl_campaign_detail ,其中将 blogger_ID 和 Campaign_id 添加为外键,其中有些其他领域。
我想从该表中删除记录。.当我执行删除操作时,它删除了记录但也给出了错误信息,
错误:
类型:ArgumentCountError
消息:函数Campaign :: camp_detls()的参数太少,第532行的D:\ XAMPP \ htdocs \ bms \ system \ core \ CodeIgniter.php中传递了0,并且恰好是1
文件名:D:\ XAMPP \ htdocs \ bms \ application \ controllers \ Campaign.php
行号:35
它工作正常,但也会显示此错误...
这是我的模特:
public function camp_detl_delete($did){
$this->db->where('detail_id', $did);
$this->db->delete('tbl_campaign_detail');
if($this->db->affected_rows() > 0){
return true;
}else{
return false;
}
}
控制器:
public function camp_detl_delete($id){
$result = $this->cm->camp_detl_delete($id);
if($result){
$this->session->set_flashdata('success_msg', 'Record deleted successfully');
}else{
$this->session->set_flashdata('error_msg', 'Faill to delete record');
}
redirect(base_url('campaign/camp_detls/')); //this should be directed to particular id of camp_detls
}
然后查看:
$did = $cmp->detail_id;
<a href="<?php echo base_url('campaign/camp_detl_delete/' .$did); ?>" onclick="return confirm('Do you want to delete this record?');">
<span class="glyphicon glyphicon-trash"></span>
</a>
但在第35行中显示错误的地方是:
function camp_detls($id){
$data['camps'] = $this->cm->camp_detailByID($id);
$data['campaign'] = $this->cm->getCampaignsById($id);
$data['blogger'] = $this->cm->getAllBloggers();
$data['cat'] = $this->cm->getAllCategory();
$this->load->view('layout/header');
$this->load->view('campaign/campaign_detail', $data);
$this->load->view('layout/footer');
}
请帮助,我该如何消除该错误? 我只想简单地删除它。
答案 0 :(得分:0)
消息:函数Campaign :: camp_detls()的参数太少,0 通过(...)
此错误对您来说意味着您定义的函数(camp_detls()
)并要求$id
,因为没有传递任何参数。
我想问题出在那行
redirect(base_url('campaign/camp_detls/')); //this should be directed to particular id of camp_detls
如暗示的建议,但请看。在这里您想重定向到特定的camp_detls
,但不提供$id
。