如何检测输入文件是否包含某些字段

时间:2018-10-26 06:23:47

标签: java

我这里有这段代码,需要检测输入文件中的任何行是否不包含名字,姓氏或等级。然后,它需要为不正确的行引发有意义的异常。我在设置if语句以检测每行内容时遇到麻烦。我知道inputFile.next一次只能读一个字,我很确定我需要为整行创建另一个变量并合并inputFile.nextLine。如果我从输入文件中取出名称或等级,则会抛出ArrayOutOfBounds异常,因为它希望看到三个单词。我想我真正想问的是如何检查行中是否包含三个单词。这是我的代码示例...

(被注释掉的代码部分是作业的另一部分,需要检查是否任何成绩在0到100之间,如果是,则抛出异常,这部分我可以正常运行。)

我的输入文件:

迈克·托尼98.7

玛丽汤姆65.8

安·托马斯95.1

亚历克斯·莱德178.6

package classwork11_2;

import java.io.*;
import java.util.ArrayList;
import java.util.Scanner;


public class Classwork11_2 {

public static void main(String[] args)throws IOException{


    File input = new File("students.txt");

    Scanner inputFile = new Scanner(input);
    PrintWriter output = new PrintWriter("average.txt");

    ArrayList<Student> array = new ArrayList<>();

    double average = 0;
    String name = "";
    String header = "Average:";
    double sum = 0;

    while(inputFile.hasNext()){

        String firstLine = inputFile.nextLine();
        String[] word = firstLine.split(" ");

        String fName = inputFile.next();
        String lName = inputFile.next();
        String grades = inputFile.next();

        try{
         /*double g = Double.parseDouble(grades);
         if(g < 0 || g > 100)
            throw new MyException(g);*/

          if(word[0] == null || word[1] == null || word[2] == null)
              throw new MyException("The names don't exist");
      }
        catch(MyException e){

          System.out.println("Parsing line with " + fName + " " + lName + " 
" + grades + " gave the following error: " + e.getMessage());
    }

        Student student = new Student(fName, lName, grades);
        array.add(student);
        name += student.getfName() + " " + student.getlName() + ", ";

    }
    for(Student i : array){

        double num = Double.parseDouble(i.getGrade());
        sum += num;
        average = sum / array.size();
    }

    System.out.println(name.substring(0, name.length()-2));
    System.out.printf("%-15s%10.1f\n", header, average);
    inputFile.close();
    output.close();

}
}

我的异常类:

    package chapter11_homework;


public class InvalidStringException extends Exception{


    public InvalidStringException(String msg){

        super(msg);
    }
}

1 个答案:

答案 0 :(得分:0)

您调用了calcWage方法,但是对它返回的值没有做任何事情。您可以将该值存储在变量中,然后打印该变量:

double wage = calcWage(sum, hourRate);
JOptionPane.showMessageDialog(null, String.format("Amount paid should be: $%.2f\n",wage));

或者您可以直接打印方法返回的值:

JOptionPane.showMessageDialog(null, String.format("Amount paid should be: $%.2f\n",calcWage(sum, hourRate)));
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