Question

我试图将下面的表格汇总为3Month，6Month，9Month等一行，但是由于mysql错误而卡住了。我确实查找了其他类似的帖子，并用大写字母替换了GROUP BY别名，但仍然说包含非聚合列。任何帮助将不胜感激。

mysql> SELECT ith.ItemCode, ith.TransactionDate, DATEDIFF(CURDATE(), ith.TransactionDate) AS Date_Diff,
    ->  (CASE WHEN DATEDIFF(CURDATE(), ith.TransactionDate) BETWEEN 0 AND 90 THEN ith.TransactionQty ELSE 0 END) AS 0_90_Days,
    ->  (CASE WHEN DATEDIFF(CURDATE(), ith.TransactionDate) BETWEEN 91 AND 180 THEN ith.TransactionQty ELSE 0 END) AS 91_180_Days,
    ->  (CASE WHEN DATEDIFF(CURDATE(), ith.TransactionDate) BETWEEN 181 AND 270 THEN ith.TransactionQty ELSE 0 END) AS 181_270_Days,
    ->  (CASE WHEN DATEDIFF(CURDATE(), ith.TransactionDate) > 270 THEN ith.TransactionQty ELSE 0 END) AS Over_270_Days
    ->
    -> FROM im_itemtransactionhistory ith, ci_item i
    -> WHERE ith.TransactionCode = 'PO'
    -> AND ith.TransactionDate >= '2018-01-01'
    -> AND ith.ItemCode = i.ItemCode
    -> AND i.TotalQuantityOnHand > 0
    -> AND ith.ItemCode = 512619
    -> GROUP BY ith.ItemCode, ith.TransactionDate, ith.TransactionQty
    ->
    -> ORDER BY ith.TransactionDate ASC;
+----------+-----------------+-----------+-----------+-------------+--------------+---------------+
| ItemCode | TransactionDate | Date_Diff | 0_90_Days | 91_180_Days | 181_270_Days | Over_270_Days |
+----------+-----------------+-----------+-----------+-------------+--------------+---------------+
|   512619 | 2018-03-19      |       220 |         0 |           0 |         1200 |             0 |
|   512619 | 2018-05-10      |       168 |         0 |        3600 |            0 |             0 |
|   512619 | 2018-05-11      |       167 |         0 |         600 |            0 |             0 |
|   512619 | 2018-06-15      |       132 |         0 |        3600 |            0 |             0 |
|   512619 | 2018-06-26      |       121 |         0 |        2400 |            0 |             0 |
|   512619 | 2018-07-23      |        94 |         0 |        2400 |            0 |             0 |
|   512619 | 2018-07-26      |        91 |         0 |        1200 |            0 |             0 |
|   512619 | 2018-09-10      |        45 |      1200 |           0 |            0 |             0 |
|   512619 | 2018-09-10      |        45 |      2400 |           0 |            0 |             0 |
|   512619 | 2018-10-16      |         9 |      1092 |           0 |            0 |             0 |
+----------+-----------------+-----------+-----------+-------------+--------------+---------------+

这就是我尝试过的。

SELECT ith.ItemCode, ith.TransactionCode, i.TotalQuantityOnHand, DATEDIFF(CURDATE(), ith.TransactionDate),
 (CASE WHEN DATEDIFF(CURDATE(), ith.TransactionDate) BETWEEN 0 AND 90 THEN ith.TransactionQty ELSE 0 END) AS 0_90_Days,
 (CASE WHEN DATEDIFF(CURDATE(), ith.TransactionDate) BETWEEN 91 AND 180 THEN ith.TransactionQty ELSE 0 END) AS 91_180_Days,
 (CASE WHEN DATEDIFF(CURDATE(), ith.TransactionDate) BETWEEN 181 AND 270 THEN ith.TransactionQty ELSE 0 END) AS 181_270_Days,
 (CASE WHEN DATEDIFF(CURDATE(), ith.TransactionDate) > 270 THEN ith.TransactionQty ELSE 0 END) AS Over_270_Days,
 SUM(CASE WHEN DATEDIFF(CURDATE(), ith.TransactionDate) BETWEEN 0 AND 90 THEN ith.TransactionQty ELSE 0 END) AS 3m_total,
 SUM(CASE WHEN DATEDIFF(CURDATE(), ith.TransactionDate) BETWEEN 91 AND 180 THEN ith.TransactionQty ELSE 0 END) AS 6m_total,
 SUM(CASE WHEN DATEDIFF(CURDATE(), ith.TransactionDate) BETWEEN 181 AND 270 THEN ith.TransactionQty ELSE 0 END) AS 9m_total,
 SUM(CASE WHEN DATEDIFF(CURDATE(), ith.TransactionDate) > 270 THEN ith.TransactionQty ELSE 0 END) AS Over9m_total

FROM im_itemtransactionhistory ith, ci_item i
WHERE ith.TransactionCode = 'PO'
AND ith.TransactionDate >= '2018-01-01'
AND ith.ItemCode = i.ItemCode
AND i.TotalQuantityOnHand > 0
AND ith.ItemCode = 512619
GROUP BY ith.ItemCode,
 (CASE WHEN DATEDIFF(CURDATE(), ith.TransactionDate) BETWEEN 0 AND 90 THEN ith.TransactionQty ELSE 0 END),
 (CASE WHEN DATEDIFF(CURDATE(), ith.TransactionDate) BETWEEN 91 AND 180 THEN ith.TransactionQty ELSE 0 END),
 (CASE WHEN DATEDIFF(CURDATE(), ith.TransactionDate) BETWEEN 181 AND 270 THEN ith.TransactionQty ELSE 0 END),
 (CASE WHEN DATEDIFF(CURDATE(), ith.TransactionDate) > 270 THEN ith.TransactionQty ELSE 0 END)

ORDER BY ith.TransactionDate ASC

错误代码将返回

#1055 - Expression #4 of SELECT list is not in GROUP BY clause and contains nonaggregated column 'mas90.ith.TransactionDate' which is not functionally dependent on columns in GROUP BY clause; this is incompatible with sql_mode=only_full_group_by

这是我想要的输出。

+----------+-----------+-------------+--------------+---------------+
| ItemCode | 0_90_Days | 91_180_Days | 181_270_Days | Over_270_Days |
+----------+-----------+-------------+--------------+---------------+
|   512619 |      4692 |       13800 |         1200 |             0 |
+----------+-----------+-------------+--------------+---------------+

Answer 1

在罗伯特·科克（Robert Kock）的帮助下，我可以通过下面的查询解决此问题。

SELECT ith.ItemCode, TEST1.total, TEST2.0_90_Days, TEST3.91_180_Days, TEST4.181_270_Days, TEST5.Over_270_Days

FROM im_itemtransactionhistory ith, 

 (SELECT ith.ItemCode, SUM(ith.TransactionQty) AS total
  FROM im_itemtransactionhistory ith
  WHERE ith.TransactionCode = 'PO'
  AND ith.ItemCode = 512619
  AND ith.TransactionDate >= '2018-01-01'
  GROUP BY ith.ItemCode
 ) AS TEST1,

 (SELECT ith.ItemCode, SUM(CASE WHEN DATEDIFF(CURDATE(), ith.TransactionDate) BETWEEN 0 AND 90 THEN ith.TransactionQty ELSE 0 END) AS 0_90_Days
  FROM im_itemtransactionhistory ith
  WHERE ith.TransactionCode = 'PO'
  AND ith.ItemCode = 512619
  AND ith.TransactionDate >= '2018-01-01'
  GROUP BY ith.ItemCode
  ) AS TEST2,

 (SELECT ith.ItemCode, SUM(CASE WHEN DATEDIFF(CURDATE(), ith.TransactionDate) BETWEEN 91 AND 180 THEN ith.TransactionQty ELSE 0 END) AS 91_180_Days
  FROM im_itemtransactionhistory ith
  WHERE ith.TransactionCode = 'PO'
  AND ith.ItemCode = 512619
  AND ith.TransactionDate >= '2018-01-01'
  GROUP BY ith.ItemCode
  ) AS TEST3,

 (SELECT ith.ItemCode, SUM(CASE WHEN DATEDIFF(CURDATE(), ith.TransactionDate) BETWEEN 181 AND 270 THEN ith.TransactionQty ELSE 0 END) AS 181_270_Days
  FROM im_itemtransactionhistory ith
  WHERE ith.TransactionCode = 'PO'
  AND ith.ItemCode = 512619
  AND ith.TransactionDate >= '2018-01-01'
  GROUP BY ith.ItemCode
  ) AS TEST4,

 (SELECT ith.ItemCode, SUM(CASE WHEN DATEDIFF(CURDATE(), ith.TransactionDate) > 270 THEN ith.TransactionQty ELSE 0 END) AS Over_270_Days
  FROM im_itemtransactionhistory ith
  WHERE ith.TransactionCode = 'PO'
  AND ith.ItemCode = 512619
  AND ith.TransactionDate >= '2018-01-01'
  GROUP BY ith.ItemCode
  ) AS TEST5


WHERE ith.TransactionCode = 'PO'
AND ith.TransactionDate >= '2018-01-01'
AND ith.ItemCode = 512619
AND ith.ItemCode = TEST1.ItemCode
AND ith.ItemCode = TEST2.ItemCode

GROUP BY ith.ItemCode, TEST2.0_90_Days, TEST3.91_180_Days, TEST4.181_270_Days, TEST5.Over_270_Days

并发布结果希望对遇到相同问题的人有所帮助。

+----------+-------+-----------+-------------+--------------+---------------+
| ItemCode | total | 0_90_Days | 91_180_Days | 181_270_Days | Over_270_Days |
+----------+-------+-----------+-------------+--------------+---------------+
|   512619 | 19692 |      4692 |       13800 |         1200 |             0 |
+----------+-------+-----------+-------------+--------------+---------------+

在Case By语句中包装案例MySQL

1 个答案: