Question

我使用js通过此php运行ajax：

 function ajax_Person() { ?>
    <script type="text/javascript">
    jQuery("#createCat").on("click", function(e){
      e.preventDefault();
      person();
    });
    function person(){
      jQuery.ajax({
        url: '<?php echo admin_url('admin-ajax.php'); ?>',
        type: 'post',
        data: { action: 'data_person', catName: jQuery('#newCat').val(), catDesc: jQuery('#descRiption').val() },
        success: function(data) {
          jQuery(".modal-body").html("Done!");
        }
      });
    }
    </script>
  <?php }

然后我跑

  function data_person(){
    $catname = $_POST['catName'];
    $catdesc = $_POST["catDesc"];
    $cat_ID = get_cat_ID( sanitize_title_for_query($catname) );  
    // Check if category exists
    if($cat_ID == 0) {
        $cat_name = $catname;  
        $cat_desc = $catdesc;
        $cat_slug = sanitize_title_with_dashes($cat_name);
        $my_cat = array(
          'cat_name' => $cat_name, 
          'category_description' => $cat_desc, 
          'category_nicename' => $cat_slug, 
          'category_parent' => 0
        );
        if( wp_insert_category( $my_cat ) ) {
          echo 'Category added successfully';
        } else {
          echo 'Error while creating new category';
        }
    } else {
      echo 'That category already exists';
    }
  }

在两种情况下，我都得到“完成！”作为回应。我需要根据以下内容设置回复：

   if( wp_insert_category( $my_cat ) ) {
          echo 'Category added successfully';
        } else {
          echo 'Error while creating new category';
        }
    } else {
      echo 'That category already exists';
    }

如果我将它们作为标准php运行，则上述php位有效。

Answer 1

尝试：

在您的PHP上

 if( wp_insert_category( $my_cat ) ) {
      echo json_encode( 'Category added successfully');
    } else {
      echo json_encode( 'Error while creating new category');
    }
} else {
  echo json_encode( 'That category already exists');
}

在js上

 $(".modal-body").html("Done!");

使用

  $(".modal-body").html(data);

如何从php获取ajax响应？

1 个答案: