Question

我遇到错误：

选择列表中的“ people.playerID”列无效，因为它是既不包含在汇总函数中，也不包含

select 
     p.playerid,NameGiven + ' ( ' + namefirst + ' ) ' + nameLast as [Full Name], 
     teamid, myr,yearid, format(AVG(salary),'C') as [Player Average Salary]
from 
     Salaries s, 
     people p , 
    (select playerid ,max(yearid) as myr 
     from Salaries 
     group by playerID) m
where 
      s.playerID=p.playerID and 
      m.playerID=s.playerID

Answer 1

首先，请避免使用旧的联接表样式。使用ANSI

的JOIN样式

对于您的错误，基本上所有未聚合的列都必须出现在GROUP BY子句中。就您的情况而言，您错过了整个GROUP BY

select 
       p.playerid,
       NameGiven + ' ( ' + namefirst + ' ) ' + nameLast as [Full Name], 
       teamid, 
       myr,
       yearid,
       format(AVG(salary),'C') as [Player Average Salary]    
from       Salaries s
inner join people p    on s.playerID = p.playerID
inner join (
               select playerid ,max(yearid) as myr 
               from   Salaries 
               group by playerID
            ) m        on m.playerID = s.playerID
group by
       p.playerid,
       NameGiven + ' ( ' + namefirst + ' ) ' + nameLast, 
       teamid, 
       myr,
       yearid

Answer 2

您使用的是旧的join，这不好join。我建议您不要使用它。在此处阅读Bad Habits to kick : Using Old Style Joins

select 
     p.playerid,NameGiven + ' ( ' + namefirst + ' ) ' + nameLast as [Full Name], 
     teamid, myr,yearid, format(AVG(salary),'C') as [Player Average Salary]
from 
     Salaries s 
     Inner Join People p on  s.playerID=p.playerID 
     Inner Join 
           (select 
                 playerid ,max(yearid) as myr 
            from 
                 Salaries 
            group by 
                 playerID) m on m.playerID=s.playerID
Group By
       P.PlayerID, NameGiven + ' ( ' + namefirst + ' ) ' + nameLast,
       teamid, myr, yearid

您的错误已清除。只需aggregate加上完整的表达式即可。

Answer 3

要显示详细信息并汇总这些详细信息的值，可以使用窗口函数。假设您正在寻找被检查球员的平均工资（就像您对myr所做的那样），则为：

SELECT
  p.playerid,
  NameGiven + ' ( ' + namefirst + ' ) ' + nameLast AS [Full Name],
  teamid,
  MAX(yearid) OVER (PARTITION BY p.playerid) AS myr,
  yearid,
  AVG(salary) OVER (PARTITION BY p.playerid) AS [Player Average Salary]
FROM Salaries s
  INNER JOIN people p ON s.playerID = p.playerID;

格式化应在使用记录的客户端应用程序或报告中完成。

出现错误：选择列表中的“ people.playerID”列无效，因为任一聚合函数均未包含该列

3 个答案: