Question

我正在尝试使其代码返回的年份不同。输入：

def rule_of_72():
    view_percent = 1
    percent = 0.01
    value = 10
    doubled = value * 2
    years = 1
    d = 0
    while(d < value):
        d = value * percent * years
        years += 1
    print("interest rate %", "Rule of 72", "Actual")
    while(view_percent <= 20):
        print("     ", view_percent, "         ",     72//view_percent, "       ", years - 1)
        view_percent += 1
        percent += 0.01

rule_of_72()

Output

它不应该一直打印100张它会打印出以年为单位的时间，以单利计算，它需要200倍的时间

我没人知道如何解决这个问题吗？

Answer 1

您应该在第二个循环中更新年份，如下所示：

while(view_percent <= 20):
    years=......
    print("     ", view_percent, "         ",     72//view_percent, "       ", years - 1)
    view_percent += 1
    percent += 0.01

输入您的计算结果而不是......

Answer 2

你是这个意思吗？

while(view_percent <= 20):
    years -= 1
    print("     ", view_percent, "         ",     72//view_percent, "       ", years)
    view_percent += 1
    percent += 0.01

输出：

interest rate % Rule of 72 Actual
      1           72         100
      2           36         99
      3           24         98
      4           18         97
      5           14         96
      6           12         95
      7           10         94
      8           9         93
      9           8         92
      10           7         91
      11           6         90
      12           6         89
      13           5         88
      14           5         87
      15           4         86
      16           4         85
      17           4         84
      18           4         83
      19           3         82
      20           3         81

我如何使while循环更改其输出数字

2 个答案: