Question

我尝试在cakephp 3.6中编写此查询：

SELECT `Group`.`id`, `Group`.`name`, `Group`.`created`, `Group`.`modified`, (SELECT count(*)
                            FROM `positions` where Group.id = positions.group_id) AS "count" FROM `groups` AS `Group`

我可以使用原始查询来获取结果，但是如何使用ORM \ Query来实现呢？

Answer 1

有些喜欢这个。

$query = $this->Groups->find();
$query->select([
        'Groups.id',
        'Groups.name', 
        'Groups.created', 
        'Groups.modified',
        'count' => $query->func()->count('Positions.id')
    ])->leftJoinWith('Positions')
      ->group('Groups.id');

Answer 2

最后我找到了解决方法：

identitytoolkit

查看日志时，我得到：

$position = TableRegistry::getTableLocator()->get('Positions');
        $q = $position->find();
        $q->select([$q->func()->count('*')])
                    ->where(['Positions.group_id = Groups.id']);
        $query = $this->Groups->find()
         ->select(['id',  'name', 'created', 'modified' , 'count' => $q]);

在子查询中选择count（*）-cakephp 3.6

2 个答案: