Question

如果用户以特定顺序更改某些设置，我需要在数据库中设置时间戳记，我将在下面为您提供更多详细信息！

数据库：

#USERS
user_id  user_name  user_password ...
1        Adam       ....
2        Bryan      ....
3        Claire     ....
4        Donna      ....

#PROJECTS
project_id  project_name  project_status  project_start  project_delivery
1           Name 1        Inbox           2018-01-01     2018-01-10         
2           Name 2        Working         2018-01-03     2018-01-12
3           Name 3        Delivered       2018-01-03     2018-01-04
4           Name 4        Delivered       2018-01-04     2018-01-04

当前查询：

$query = "

UPDATE projects

SET

project_name = '".$mysqli->real_escape_string($_POST['project_name'])."',

project_status = '".$mysqli->real_escape_string($_POST['project_status'])."',

project_start = '".$mysqli->real_escape_string($_POST['project_start'])."',

project_delivery = '".$mysqli->real_escape_string($_POST['project_delivery'])."'

WHERE

project_id = '".$mysqli->real_escape_string($_REQUEST['id'])."'

";

PHP：

基本上只是一个选择/选项和输入字段。请注意，project_status是一个选择/选项。

问题：

简而言之，当项目从“收件箱”移动到“ project_start中的工作状态”时，我想用今天的时间戳更新project_status。

将项目从“正在工作”移至“已交付”时，project_delivery也是如此。

关于如何实现这样的目标的任何想法吗？

Answer 1

您可以这样尝试

 SET project_start = CASE
                     WHEN project_status = 'Inbox' THEN CURDATE()
                     ELSE project_start
                     END 
     project_delivery = CASE
                        WHEN project_status = 'Working' THEN CURDATE() 
                        ELSE project_delivery
                        END 
 WHERE   ....

当项目从特定状态移至另一特定状态时，更新/设置SQL查询时间戳

1 个答案: