Question

我对Mule ESB 3.8.4中的DataWeave具有以下要求，其中shipDate_n，shipMethod_n和trackingNumber_n将在以下情况下从1变为n 输入有效载荷。我需要根据密钥中下划线后的数字对数据进行分组：

输入有效载荷：

[{
    "shipDate_1": "2010-01-11T07:00:00Z",
    "shipDate_2": "2010-02-11T07:00:00Z",
    "shipDate_3": "2010-03-11T07:00:00Z",
    "shipMethod_1": "UPS1 Ground",
    "shipMethod_2": "UPS2 Ground",
    "shipMethod_3": "UPS3 Ground",
    "trackingNumber_1": "1",
    "trackingNumber_2": "2",
    "trackingNumber_3": "3"
}]

必需的输出：

[{
    "trackingInfo": [{
            "trackingNbr": "1",
            "shipMethod": "UPS1 Ground",
            "shipDate": "2010-01-11T07:00:00Z"
        },
        {
            "trackingNbr": "2",
            "shipMethod": "UPS2 Ground",
            "shipDate": "2010-02-11T07:00:00Z"
        },
        {
            "trackingNbr": "3",
            "shipMethod": "UPS3 Ground",
            "shipDate": "2010-03-11T07:00:00Z"
        }
    ]
}]

Answer 1

您可以使用pluck方法对n这样的字段数进行计数，然后迭代n/3次并动态地形成键以从输入中获取数据。以下代码适用于给定的输入

代码

%dw 1.0
%output application/json
%var data = payload[0]
%var dataSet = (sizeOf (data pluck $$ )) / 3
%var startIndex = 1
---
[trackingInfo : [ startIndex[0] .. dataSet] map {
    "trackingNbr": data[("trackingNumber_" ++ $)],
    "shipMethod":data[("shipMethod_" ++ $)],
    "shipDate": data[("shipDate_" ++ $)]
}]

输入-

[
    {
        "shipDate_1": "2010-01-11T07:00:00Z",
        "shipDate_2": "2010-02-11T07:00:00Z",
        "shipMethod_1": "UPS1 Ground",
        "shipMethod_2": "UPS2 Ground",
        "trackingNumber_1": "1",
        "trackingNumber_2": "2"
    }
]

输出-

[
  {
    "trackingInfo": [
      {
        "trackingNbr": "1",
        "shipMethod": "UPS1 Ground",
        "shipDate": "2010-01-11T07:00:00Z"
      },
      {
        "trackingNbr": "2",
        "shipMethod": "UPS2 Ground",
        "shipDate": "2010-02-11T07:00:00Z"
      }
    ]
  }
]

另一种方法是基于输入中存在的trackingNumber个字段的计数

%dw 1.0
%output application/json
%var data = payload[0]
%var dataSet =  sizeOf ((data pluck $$ ) filter ($ contains "trackingNumber"))
%var startIndex = 1
---
[trackingInfo : [startIndex[0] .. dataSet] map {
    "trackingNbr": data[("trackingNumber_" ++ $)],
    "shipMethod":data[("shipMethod_" ++ $)],
    "shipDate": data[("shipDate_" ++ $)]
}]

HTH

Dataweave 1.0中的Groupby关键段

1 个答案: