Question

因此，我的数据当前以客户的名字为后缀。可能是：MISS | MRS | MISS | MR | DR | MS | JT | CHD | CHLD | DEAN | REV | MRI | EARL | DRI | DEAN | MSI。

我正试图摆脱结尾处的后缀。

以下是数据示例

名字：

RUTH ANNE MRS

CHRISTOPHER MR

这是我编写的代码，但是我的代码只删除了一个字母，因此露丝·安妮（Ruth Anne MRS）会显示为RUTH ANNE MR

 REPLACE(SUBSTRING(First_Name, CHARINDEX('MISS|MRS|MISS|MR|DR|MS|JT|CHD|CHLD|DEAN|REV|MRI|EARL|DRI|DEAN|MSI', First_Name), LEN(First_Name)), 'MISS|MRS|MISS|MR|DR|MS|JT|CHD|CHLD|DEAN|REV|MRI|EARL|DRI|DEAN|MSI', '   ')

Answer 1

编写SQL：

获取REVERSE字符串中第一个空格字符的CHARINDEX，

检查该子字符串是否适合后缀模式之一，

如果是这样，则返回原始字符串（使用LEFT）缩短了该子字符串的长度。

Answer 2

您可以使用以下查询删除结尾的后缀

DECLARE @string VARCHAR(4000);

SET @string =空格（1）+'RUTH ANNE MRS';

要删除（单词） AS（选择'MISS'COLLATE SQL_LATIN1_GENERAL_CP1_CI_AS UNION ALL 选择'MRS'COLLATE SQL_LATIN1_GENERAL_CP1_CI_AS UNION ALL 选择'MISS'COLLATE SQL_LATIN1_GENERAL_CP1_CI_AS UNION ALL 选择'MR'COLLATE SQL_LATIN1_GENERAL_CP1_CI_AS UNION ALL 选择'DR'COLLATE SQL_LATIN1_GENERAL_CP1_CI_AS UNION ALL 选择'MS'COLLATE SQL_LATIN1_GENERAL_CP1_CI_AS UNION ALL 选择'JT'COLLATE SQL_LATIN1_GENERAL_CP1_CI_AS UNION ALL SELECT'CHD'COLLATE SQL_LATIN1_GENERAL_CP1_CI_AS UNION ALL SELECT'CHLD'COLLATE SQL_LATIN1_GENERAL_CP1_CI_AS UNION ALL 选择'DEAN'COLLATE SQL_LATIN1_GENERAL_CP1_CI_AS UNION ALL SELECT'REV'COLLATE SQL_LATIN1_GENERAL_CP1_CI_AS UNION ALL 选择'MRI'COLLATE SQL_LATIN1_GENERAL_CP1_CI_AS UNION ALL SELECT'EARL'COLLATE SQL_LATIN1_GENERAL_CP1_CI_AS UNION ALL 选择'DRI'COLLATE SQL_LATIN1_GENERAL_CP1_CI_AS UNION ALL SELECT'DEAN'COLLATE SQL_LATIN1_GENERAL_CP1_CI_AS UNION ALL
选择'MSI'COLLATE SQL_LATIN1_GENERAL_CP1_CI_AS ） SELECT @string = 更换（ @string COLLATE SQL_LATIN1_GENERAL_CP1_CI_AS， ToRemove.word收集SQL_LATIN1_GENERAL_CP1_CI_AS，空格（1）收集SQL_LATIN1_GENERAL_CP1_CI_AS ）从到删除 CHARINDEX在哪里（ ToRemove.word收集SQL_LATIN1_GENERAL_CP1_CI_AS， @string COLLATE SQL_LATIN1_GENERAL_CP1_CI_AS ）> 0;

SELECT @string;

Answer 3

如果将标题存储到表中，则可以通过单个SELECT来完成

准备测试数据

CREATE TABLE #titles (title nvarchar(10));
INSERT INTO #titles (title) VALUES ('M.'), ('Mme'), ('Mlle');
CREATE TABLE #data (fullname nvarchar(100));
INSERT INTO #data (fullname) VALUES
('John Doe M.'),
('Mary Jones Mme'),
('Doctor Who Mme'),
('Leia Organa Mlle')

查询

SELECT 
    d.fullname, 
    SUBSTRING(d.fullname, 1, LEN(d.fullname) - LEN(t.title)) AS new_fullname,
    SUBSTRING(d.fullname, LEN(d.fullname) - LEN(t.title) + 1, LEN(t.title)) AS found_title
FROM #data d LEFT JOIN #titles t ON d.fullname LIKE '%' + t.title

结果

fullname                       new_fullname                   found_title
------------------------------ ------------------------------ ------------------------------
John Doe M.                    John Doe                       M.
Mary Jones Mme                 Mary Jones                     Mme
Doctor Who Mme                 Doctor Who                     Mme
Leia Organa Mlle               Leia Organa                    Mlle

在SQL Server（MISS，DR）的末尾删除后缀

3 个答案: