所以我正在研究一个Java项目，其中涉及创建一个可根据温度调整价格的苏打水机器。我似乎无法弄清楚在接受用户付款时如何确保机器不接受便士。
我觉得我编码过度，但是我处于机智的境地，因为我不知道如何不接受便士。
import java.util.*;
import java.text.*;
public class SodaMachine extends SodaTester
{
public static void main(String[] args)
{
double temp;
double money;
double change;
double price1 = .50;
double price2 = .55;
double price3 = .60;
double price4 = .65;
double price5 = .75;
double price6 = .80;
double price7 = .85;
double price8 = .90;
double price9 = 1.00;
System.out.println("Hi there! Please enter the temperature in Farenheit:");
Scanner scan = new Scanner(System.in);
temp = scan.nextDouble();
DecimalFormat fmt = new DecimalFormat("0.#");
NumberFormat fmt2 = NumberFormat.getCurrencyInstance();
if (temp < 40 || temp > 120)
{
System.out.println("Invalid input. Temperature should be between 40 and 120 degrees Farenheit.");
while (temp < 40 || temp > 120)
{
temp = scan.nextDouble();
System.out.println("The rounded temperature in degrees Farenheit is: " + fmt.format(temp));
System.out.println("Invalid input. Temperature should be between 40 and 120 degrees Farenheit.");
}
}
if(temp < 50 && temp >= 40)
{
System.out.println("The rounded temperature in degrees Farenheit is: " + fmt.format(temp));
System.out.println("The price is: " + fmt2.format(price1));
System.out.println("Please insert amount of payment: ");
money = scan.nextDouble();
while (money < price1)
{
System.out.println("Invalid input please try again. Your total is: " + fmt2.format(price1));
money = scan.nextDouble();
}
change = money - price1;
System.out.println("Your Change is: " + fmt2.format(change));
}else if (temp >= 50 && temp <= 60) {
System.out.println("The rounded temperature in degrees Farenheit is: " + fmt.format(temp));
System.out.println("The price is: " + fmt2.format(price2));
System.out.println("Please insert amount of payment: ");
money = scan.nextDouble();
while (money < price2)
{
System.out.println("Invalid input please try again. Your total is: " + fmt2.format(price2));
money = scan.nextDouble();
}
change = money - price2;
System.out.println("Your Change is: " + fmt2.format(change));
}else if (temp > 60 && temp <= 65) {
System.out.println("The rounded temperature in degrees Farenheit is: " + fmt.format(temp));
System.out.println("The price is: " + fmt2.format(price3));
System.out.println("Please insert amount of payment: ");
money = scan.nextDouble();
while (money < price3)
{
System.out.println("Invalid input please try again. Your total is: " + fmt2.format(price3));
money = scan.nextDouble();
}
change = money - price3;
System.out.println("Your Change is: " + fmt2.format(change));
}else if (temp > 65 && temp <= 70) {
System.out.println("The rounded temperature in degrees Farenheit is: " + fmt.format(temp));
System.out.println("The price is: " + fmt2.format(price4));
System.out.println("Please insert amount of payment: ");
money = scan.nextDouble();
while (money < price4)
{
System.out.println("Invalid input please try again. Your total is: " + fmt2.format(price4));
money = scan.nextDouble();
}
change = money - price4;
System.out.println("Your Change is: " + fmt2.format(change));
}else if (temp > 70 && temp <= 75) {
System.out.println("The rounded temperature in degrees Farenheit is: " + fmt.format(temp));
System.out.println("The price is: " + fmt2.format(price5));
System.out.println("Please insert amount of payment: ");
money = scan.nextDouble();
while (money < price5)
{
System.out.println("Invalid input please try again. Your total is: " + fmt2.format(price5));
money = scan.nextDouble();
}
change = money - price5;
System.out.println("Your Change is: " + fmt2.format(change));
}else if (temp > 75 && temp <= 80) {
System.out.println("The rounded temperature in degrees Farenheit is: " + fmt.format(temp));
System.out.println("The price is: " + fmt2.format(price6));
System.out.println("Please insert amount of payment: ");
money = scan.nextDouble();
while (money < price6)
{
System.out.println("Invalid input please try again. Your total is: " + fmt2.format(price6));
money = scan.nextDouble();
}
change = money - price6;
System.out.println("Your Change is: " + fmt2.format(change));
}else if (temp > 80 && temp <= 85) {
System.out.println("The rounded temperature in degrees Farenheit is: " + fmt.format(temp));
System.out.println("The price is: " + fmt2.format(price7));
System.out.println("Please insert amount of payment: ");
money = scan.nextDouble();
while (money < price7)
{
System.out.println("Invalid input please try again. Your total is: " + fmt2.format(price7));
money = scan.nextDouble();
}
change = money - price7;
System.out.println("Your Change is: " + fmt2.format(change));
}else if (temp > 85 && temp <= 90) {
System.out.println("The rounded temperature in degrees Farenheit is: " + fmt.format(temp));
System.out.println("The price is: " + fmt2.format(price8));
System.out.println("Please insert amount of payment: ");
money = scan.nextDouble();
while (money < price8)
{
System.out.println("Invalid input please try again. Your total is: " + fmt2.format(price8));
money = scan.nextDouble();
}
change = money - price8;
System.out.println("Your Change is: " + fmt2.format(change));
}else if (temp > 90 && temp <= 120) {
System.out.println("The rounded temperature in degrees Farenheit is: " + fmt.format(temp));
System.out.println("The price is: " + fmt2.format(price9));
System.out.println("Please insert amount of payment: ");
money = scan.nextDouble();
while (money < price9)
{
System.out.println("Invalid input please try again. Your total is: " + fmt2.format(price9));
money = scan.nextDouble();
}
change = money - price9;
System.out.println("Your Change is: " + fmt2.format(change));
}
}
}
答案 0 :(得分：2)
我不会详细介绍您当前的代码，但是您基本上想检查一下从用户模-0.05读取的十进制值是否等于0（因此它没有余）。其中的一个问题是，当您使用double时，浮点精度会干扰支票，这就是为什么您总是想使用java.math.BigDecimal进行货币计算的原因。
这里有个例子：
BigDecimal input = new BigDecimal(scanner.next());
if(input.remainder(new BigDecimal("0.05")).compareTo(BigDecimal.ZERO) == 0){
System.out.println("Input "+input+" is valid!");
} else{
System.out.println("Input "+input+" is not valid!");
}
对于输入"1"，"1.00"，"1.05"，"4.35"，"1.01"，"3.21"，"4.68"，它将输出以下：
Input 1 is valid!
Input 1.00 is valid!
Input 1.05 is valid!
Input 4.35 is valid!
Input 1.01 is not valid!
Input 3.21 is not valid!
Input 4.68 is not valid!
由于BigDecimal对于Java的新用户可能会造成很大的困扰，您也许可以让用户输入以美分（例如整数）为单位的金额，在这种情况下，可能是这样的：
int input = scanner.nextInt();
if(input % 5 == 0){
System.out.println("Input "+input+" is valid!");
} else{
System.out.println("Input "+input+" is not valid!");
}
对于输入"100"，"105"，"435"，"101"，"321"，"468"，它将输出以下内容：
Input 100 is valid!
Input 105 is valid!
Input 435 is valid!
Input 101 is not valid!
Input 321 is not valid!
Input 468 is not valid!
编辑：由于有一段时间，我用可重用的方法重新设计了您的解决方案。
请仔细查看我的工作，如果对特定部分有任何疑问，请告诉我。现在，它使用递归方法，直到用户输入有效输入为止。方法中的boolean showMessage参数仅显示一次"Please enter X"消息。
import java.lang.IllegalArgumentException;
import java.lang.NumberFormatException;
import java.math.BigDecimal;
import java.text.NumberFormat;
import java.util.InputMismatchException;
import java.util.Scanner;
public class SodaMachine{
private static final String currencySymbol = "$";
private static final BigDecimal roundOn = new BigDecimal("0.05");
private Scanner scanner;
private NumberFormat currencyFormat;
public SodaMachine(){
scanner = new Scanner(System.in);
currencyFormat = NumberFormat.getCurrencyInstance();
}
public static void main(String[] args){
SodaMachine sodaMachine = new SodaMachine();
double farenheitInput = sodaMachine.enterFarenheit(true);
System.out.println("The temperature in degrees Farenheit you've entered is: " + farenheitInput);
BigDecimal price = sodaMachine.determinePrice(farenheitInput);
System.out.println("The price is: " + sodaMachine.currencyFormat.format(price));
BigDecimal payment = sodaMachine.enterPayment(price, true);
BigDecimal change = payment.subtract(price);
System.out.println("Your change is: " + sodaMachine.currencyFormat.format(change));
}
private double enterFarenheit(boolean showMessage){
if(showMessage){
System.out.println("Hi there! Please enter the temperature in Farenheit:");
}
double farenheitInput;
try{
farenheitInput = scanner.nextDouble();
} catch(InputMismatchException ex){
scanner.nextLine(); // Get rid of the invalid user-input
System.out.println("The value you've entered is not a valid. The input should be a decimal input. Please try again.");
return enterFarenheit(false);
}
if(farenheitInput < 40 | farenheitInput > 120){
System.out.println("Invalid input. Temperature should be between 40 and 120 degrees Farenheit.");
return enterFarenheit(false);
}
return farenheitInput;
}
private BigDecimal determinePrice(double farenheit){
String strPrice;
// Temperature is in the range [40, 50):
if(farenheit >= 40 && farenheit < 50){
strPrice = "0.50";
}
// Temperature is in the range [50, 60]:
else if(farenheit >= 50 && farenheit <=60){
strPrice = "0.55";
}
// Temperature is in the range (60, 65]:
else if(farenheit > 60 && farenheit <= 65){
strPrice = "0.60";
}
// Temperature is in the range (65, 70]:
else if(farenheit > 65 && farenheit <= 70){
strPrice = "0.65";
}
// Temperature is in the range (70, 75]:
else if(farenheit > 70 && farenheit <= 75){
strPrice = "0.75";
}
// Temperature is in the range (75, 80]:
else if(farenheit > 75 && farenheit <= 80){
strPrice = "0.80";
}
// Temperature is in the range (80, 85]:
else if(farenheit > 80 && farenheit <= 85){
strPrice = "0.85";
}
// Temperature is in the range (85, 90]:
else if(farenheit > 85 && farenheit <= 90){
strPrice = "0.90";
}
// Temperature is in the range (90, 120]:
else if(farenheit > 90 && farenheit <= 120){
strPrice = "1.00";
}
// Invalid temperature range:
else{
// Since we already validated the input-range, it should never go here,
// but added it just in case.
throw new IllegalArgumentException("The temperature must be in the range [40, 120]!");
}
return new BigDecimal(strPrice);
}
private BigDecimal enterPayment(BigDecimal price, boolean showMessage){
if(showMessage){
System.out.println("Please enter amount of payment: ");
}
String userInput = scanner.next();
// Remove the optional currency symbol from the user input
userInput = userInput.replace(currencySymbol, "");
BigDecimal paymentInput;
try{
paymentInput = new BigDecimal(userInput);
} catch(NumberFormatException ex){
scanner.nextLine(); // Get rid of the invalid user-input
System.out.println("The value you've entered is not a valid. The input should be a price input. Please try again.");
return enterPayment(price, false);
}
if(paymentInput.compareTo(price) < 0){
System.out.println("Your payment of " + currencyFormat.format(paymentInput) + " is too low. Please try again. The total price is: " + currencyFormat.format(price));
return enterPayment(price, false);
}
if(paymentInput.remainder(roundOn).compareTo(BigDecimal.ZERO) != 0){
System.out.println("Your payment should be rounded to " + currencyFormat.format(roundOn) + ". Please try again.");
return enterPayment(price, false);
}
return paymentInput;
}
}
答案 1 :(得分：0)
您的代码可以简化很多，但我将重点关注手头的问题。
我将创建一个函数来获取用户输入，确保其中不包含任何便士：
double getMoney(String prompt, Scanner scan)
{
double money = 0;
while(true) { // Loop until proper input
System.out.println(prompt);
money = scan.nextDouble();
// There are a few ways to determine if it has pennies.
// I will convert to int and check if it is divisible
// by 10 or 5
int i = (int)Math.round(money * 100); // Convert to pennies
if (0 == i % 5) {
// It's ok, return
return money;
}
}
}
旁注：使用浮点数表示货币是不好的做法。浮点会引入舍入误差。最好使用整数并使用最小面额存储值。在这种情况下，便士。