Question

当包含谁的两列包含data / null时，我有了表，我只想捕获不为null的行。

t1的示例

Application_channel | reason_for_joining
            call    | null
            null    | do not wish to provide
            null    | null

我希望输出为

Status
 call
 do not wish to provide

我写的查询有点像：-

select case 
when reason_for_joining is null and application_channel is not null then       application_channel
when application_channel is null and reason_for_joining is not null then 
reason_for_joining else application_channel end as status
from t1

问题是当两个列都具有我不想要的空值时，它也取空值。任何帮助表示赞赏。

Answer 1

他还想过滤那些空的，所以应该是：

select coalesce(Application_channel, reason_for_joining) as status
from t1
where coalesce(Application_channel, reason_for_joining) is not null

或者，您也可以像这样过滤：

WHERE Application_channel IS NOT NULL OR reason_for_joining IS NOT NULL

Answer 2

您要coalesce()：

select coalesce(Application_channel, reason_for_joining) as status
from t1

Answer 3

两个参数ISNULL的情况也可以做同样的工作

select ISNULL('call',null),isnull(null,'do not')

因此您可以查询

select ISNULL(Application_channel, reason_for_joining) as status
from t1
where ISNULL(Application_channel, reason_for_joining) is not null

在SQL中的情况

3 个答案: