Question

/*
ADDING NUMBERS TO ArrayLIST AND IF NEW NUMBER ENTERED SAME AS already EXISTING NUMBER
RESAULT IS DUBLICATE;
 */
private String[] phoneNumbers;

public String addPhoneNumber(String newPhoneNumber) throws SMSDataModelFullException {
    String result;

    if (numPhoneNumbers == phoneNumbers.length) {
        result = FULL;
    } else {
        boolean exists;
        exists = findPhoneNumberIndex(newPhoneNumber) != -1;
        if (exists) {
            result = DUPLICATE;
        } else {
            phoneNumbers[numPhoneNumbers] = newPhoneNumber;
            numPhoneNumbers++;
            result = newPhoneNumber;
        }
    }
    return result;
}

这对Array来说是完美的。我需要一些有关复制现有号码到列表

的帮助

private List<String> phoneNumber;

public String addPhoneNumber(String newPhoneNumber) throws SMSDataModelFullException {

    String result;

    if (maxNumPhoneNumbers!=0 && phoneNumber.size() >= maxNumPhoneNumbers) {
        throw new SMSDataModelFullException(newPhoneNumber);
    }
    else{
        boolean exist;
        exist =findPhoneNumberIndex(newPhoneNumber)!= -1;
        if(exist)
        {
            result = DUPLICATE;
        }
        else{
            phoneNumber.add(newPhoneNumber);
        }
        return  newPhoneNumber;
    }
}

这是行不通的，我在做什么错？列表中的重复项未显示某些原因。

Answer 1

public String addPhoneNumber(String newPhoneNumber) {

    String result = newPhoneNumber;

    if(!phoneNumber.contains(newPhoneNumber)){  // if it is not already in the list
       phoneNumber.add(newPhoneNumber);         // add it to the list
    }else{
       result = "DUPLICATE";                      // if number was already in the list result = DUPLICATE
    }

    return result;

}

Answer 2

您总是返回newPhoneNumber

    return  newPhoneNumber;

与第一种情况相同

...
    if (exists) {
        result = DUPLICATE;
    } else {
        phoneNumber.add(newPhoneNumber);
        result = newPhoneNumber;
    }
}
return result;

您的findPhoneNumberIndex()也可以替换为phoneNumber.contains(newPhoneNumber)

将号码添加到具有现有重复号码的列表中

2 个答案: