Question

我有一个包含重复日期的json，我想将重复日期合并到单个json对象中。数据：

 [
   {"date":"2017-06-26","mac":"66"},
   {"date":"2017-06-26","window":"400"},
   {"date":"2017-07-03","mac":"19"},
   {"date":"2017-07-03","window":"12"}
 ]

输出应为：

  [
   {"date":"2017-06-26","mac":"66","window":"400"},
   {"date":"2017-07-03","mac":"19","window":"12"}
 ]

Answer 1

这是一个执行此操作的javascript函数，您可以在传递数组并获取新的json后将JSON.stringify（...）应用于输出。

(( a ) => { 
    // used to check for already inserted dates
    let withoutDupes = { };

    if(Array.isArray(a)) {
        a.forEach( (item) => { 
            // assuming item has a "date" property inside
            if(withoutDupes[item.date]) {
                withoutDupes[item.date] = Object.assign( item, withoutDupes[item.date] );
            } else {
                withoutDupes[item.date] = item;
            }
        } );
    }

    return Object.values( withoutDupes );
})( a )

Answer 2

您可以尝试使用jq command line parser及其group_by功能：

jq '[group_by(.date)|.[]|add]' file
[
  {
    "date": "2017-06-26",
    "mac": "66",
    "window": "400"
  },
  {
    "date": "2017-07-03",
    "mac": "19",
    "window": "12"
  }
]

从数据中检查重复的日期并分配给新的json

2 个答案: