Question

未在另一个函数内调用该函数：

ch = False
while not ch:
     print("""
        1. Make a User
        2. Login in and Play
        3. Quit

   """)
     a = input("What would you like to do: ")
     if a == '1':
        un_maker()
     elif a == '2':
        player1Login()
     elif a == '3':
        input('\nEnter to exit...\n')
        quit()

当a为2时，它应该继续前进到player1Login()，但不会转到player1Login()内部的下一个函数。

player1Login()的代码及其应运行的功能：

 def player1Login():
     """ Login for player 1 """
     user1 = input("Please enter your usernames[Caps sensitive]:  ") # Asking the 
     user to input there username
     pass1 = input("Please also enter your password[Caps sensitive]: ") # Asking the user to input there password
     verfi1(user1, pass1)

  def verfi1(user1, pass1):
     """ Verfications of the user """
     with open("data.csv", "r") as f:
        reader = csv.reader(f) # makes 'reader' the csv reader of file 'f'
        for row in reader: # Looking at rows/records inside the file
            if user1 in row: # Looks for username inside the row
                if pass1 in row[1]:
                     print("Player 1 Confirmed") 
                     player2Login()
                elif pass1 != row[1] or reader == '':
                     print("""You have entered the wrong Username/Password for Player 1
                              This could be due to:
                              1. Inputed the wrong username/password
                              2. Inputed the wrong case in username/password
                              3. Inputed username/password that does not exit
                           """)
                     break
            else:
                 #print("Reader")
                 next(reader)

基本上，代码应在a为2，player1Login()时输出，然后移至verfi1()函数，但不是，仅返回菜单。

找到答案

def menu():
    ch = False
    optin = 0
    while not ch :
           print("""
                1. Make a User
                2. Login in and Play
                3. Quit
                """)
           optin = input("What would you like to do: ")
           if optin == '1':
               un_maker()
           elif optin == '2':
               player1Login()
           elif optin == '3':
               input('\nEnter to exit...\n')
               quit()

def player1Login():
""" Login for player 1 """
    user1 = input("Please enter your usernames[Caps sensitive]:  ") 
    pass1 = input("Please also enter your password[Caps sensitive]: ")
    boop(user1, pass1)

def boop(user1, pass1):
    with open('data.csv', 'r') as f:
        reader = csv.reader(f)
        for row in reader:
            if pass1 in row[1] and user1 in row[0]:
                 print("Username and Password found, Player 1 Confirmed")
                 player2Login(user1)
            elif pass1 not in row[1] and user1 not in row[0] and row[0] == '' :
                 print("Player Not found / Password incorrect")
                 menu()

Answer 1

您跳过/href=".+\.(?!css|js).+"/行，因此跳过了next文件中的其他用户。这可能导致data.csv永远不会为真，即使if user1 in row在您的文件中但恰好在跳过的行上。

您的代码：

user1

删除for row in reader: # Looking at rows/records inside the file if user1 in row: # Looks for username inside the row if pass1 in row[1]: print("Player 1 Confirmed") player2Login() elif pass1 != row[1] or reader == '': print("""You have entered the wrong Username/Password for Player 1 This could be due to: 1. Inputed the wrong username/password 2. Inputed the wrong case in username/password 3. Inputed username/password that does not exit """) break else: next(reader) # this skips the next条款，因为else已遍及所有行。

没有被称为python的函数

1 个答案: