Question

我已经按照有关如何完成此操作的多个教程进行了操作，并且根据我使用的脚本，我收到消息“成功导入”或类似的消息，但是我没有运气。我的CSV包含26列和大约18,000行。我已经建立了PHPMYADMIN数据库和表，并尝试了相同的脚本，只加载了少量数据，仅包含4列，而且其中一个起作用，我试图弄清楚如何使其他脚本起作用，但是运气是0。

<?php
$conn = mysqli_connect("localhost", "DB_USERNAME", "DB_PASSWORD", "DB_NAME");

if (isset($_POST["import"])) {

    $fileName = $_FILES["file"]["tmp_name"];

    if ($_FILES["file"]["size"] > 0) {

        $file = fopen($fileName, "r");

        while (($column = fgetcsv($file, 10000, ",")) !== FALSE) {
            $sqlInsert = "INSERT into TABLE_NAME (COL1,COL2,COL3,COL4,COL5,COL6,COL7,COL8,COL9,COL10,COL11,COL12,COL13,COL14,COL15,COL16,COL17,COL18,COL19,COL20,COL21,COL22,COL23,COL24,COL25,COL26)
                   values ('" . $column[0] . "','" . $column[1] . "','" . $column[2] . "','" . $column[3] . "','" . $column[4] . "','" . $column[5] . "','" . $column[6] . "','" . $column[7] . "','" . $column[8] . "','" . $column[9] . "','" . $column[10] . "','" . $column[11] . "','" . $column[12] . "','" . $column[13] . "','" . $column[14] . "','" . $column[15] . "','" . $column[16] . "','" . $column[17] . "','" . $column[18] . "','" . $column[19] . "','" . $column[20] . "','" . $column[21] . "','" . $column[22] . "','" . $column[23] . "','" . $column[24] . "','" . $column[25] . "')";
            $result = mysqli_query($conn, $sqlInsert);

            if (! empty($result)) {
                $type = "success";
                $message = "CSV Data Imported into the Database";
            } else {
                $type = "error";
                $message = "Problem in Importing CSV Data";
            }
        }
    }
}
?>
<!DOCTYPE html>
<html>

<head>
<script src="jquery-3.2.1.min.js"></script>

<style>
body {
    font-family: Arial;
    width: 550px;
}

.outer-scontainer {
    background: #F0F0F0;
    border: #e0dfdf 1px solid;
    padding: 20px;
    border-radius: 2px;
}

.input-row {
    margin-top: 0px;
    margin-bottom: 20px;
}

.btn-submit {
    background: #333;
    border: #1d1d1d 1px solid;
    color: #f0f0f0;
    font-size: 0.9em;
    width: 100px;
    border-radius: 2px;
    cursor: pointer;
}

.outer-scontainer table {
    border-collapse: collapse;
    width: 100%;
}

.outer-scontainer th {
    border: 1px solid #dddddd;
    padding: 8px;
    text-align: left;
}

.outer-scontainer td {
    border: 1px solid #dddddd;
    padding: 8px;
    text-align: left;
}

#response {
    padding: 10px;
    margin-bottom: 10px;
    border-radius: 2px;
    display:none;
}

.success {
    background: #c7efd9;
    border: #bbe2cd 1px solid;
}

.error {
    background: #fbcfcf;
    border: #f3c6c7 1px solid;
}

div#response.display-block {
    display: block;
}
</style>
<script type="text/javascript">
$(document).ready(function() {
    $("#frmCSVImport").on("submit", function () {

        $("#response").attr("class", "");
        $("#response").html("");
        var fileType = ".csv";
        var regex = new RegExp("([a-zA-Z0-9\s_\\.\-:])+(" + fileType + ")$");
        if (!regex.test($("#file").val().toLowerCase())) {
                $("#response").addClass("error");
                $("#response").addClass("display-block");
            $("#response").html("Invalid File. Upload : <b>" + fileType + "</b> Files.");
            return false;
        }
        return true;
    });
});
</script>
</head>

<body>
    <h2>Import CSV file into Mysql using PHP</h2>

    <div id="response" class="<?php if(!empty($type)) { echo $type . " display-block"; } ?>"><?php if(!empty($message)) { echo $message; } ?></div>
    <div class="outer-scontainer">
        <div class="row">

            <form class="form-horizontal" action="" method="post"
                name="frmCSVImport" id="frmCSVImport" enctype="multipart/form-data">
                <div class="input-row">
                    <label class="col-md-4 control-label">Choose CSV
                        File</label> <input type="file" name="file"
                        id="file" accept=".csv">
                    <button type="submit" id="submit" name="import"
                        class="btn-submit">Import</button>
                    <br />

                </div>

            </form>

        </div>
               <?php
            $sqlSelect = "SELECT * FROM TABLE_NAME";
            $result = mysqli_query($conn, $sqlSelect);

            if (mysqli_num_rows($result) > 0) {
                ?>
            <table id='userTable'>
<?php

                while ($row = mysqli_fetch_array($result)) {
                    ?>

                <tbody>
                <tr>
                    <td><?php  echo $row['id']; ?></td>
                    <td><?php  echo $row['firstname']; ?></td>
                    <td><?php  echo $row['lastname']; ?></td>
                    <td><?php  echo $row['number']; ?></td>
                </tr>
                    <?php
                }
                ?>
                </tbody>
        </table>
        <?php } ?>
    </div>

</body>

</html>

Answer 1

您得到的效率非常低下并且非常不安全。例如，一旦数据中出现撇号，整个事情就会爆发。

Prepared statements可以防止data injection，并且还可以大大减少执行重复查询所需的开销。对于mysqli，这是可能的，但是PDO不再那么冗长，更现代-在新代码中应优先使用它。

这样的事情应该是一个好的开始，但是您将需要使用try / catch进行一些正确的错误检查。假定CSV中的列数等于要插入数据库中的列数。

$conn = new \PDO("mysql:host=localhost;dbname=DB_NAME", "DB_USERNAME", "DB_PASSWORD");

if (isset($_POST["import"])) {

    $fileName = $_FILES["file"]["tmp_name"];
    if ($_FILES["file"]["size"] > 0) {
        $file = fopen($fileName, "r");

        $sql = "INSERT INTO TABLE_NAME (COL1, COL2, COL3, COL4, COL5, COL6, COL7, COL8, COL9, COL10, COL11, COL12, COL13, COL14, COL15, COL16, COL17, COL18,COL19, COL20, COL21, COL22, COL23, COL24, COL25, COL26)
                VALUES (?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)"
        $stmt = $conn->prepare($sql);
        while (($column = fgetcsv($file, 10000, ",")) !== FALSE) {
            $result = $stmt->execute($column);
        }
    }
}

如何通过PHP将大型CSV文件导入MySQL？

1 个答案: