Question

因此，我需要为用户创建一个程序来输入匹配分数，并在出现提示时输入“退出”来退出。但是即使没有错误，该代码也不会运行

package Main;

import java.util.Scanner;

public class Assignment {

    public static void main(String[] args) {
        Scanner keyboard = new Scanner(System.in);

        String[] names = new String[10];


        int index = 0;
        while (index<10) {

            index++;
            System.out.print("Home team name: ");
            names[index] = keyboard.nextLine();


            System.out.print("Away team name: ");
            names[index] = keyboard.nextLine();

            System.out.print("Enter home score: ");
            names[index] = keyboard.nextLine();

            System.out.print("Enter away score: ");
            names[index] = keyboard.nextLine();

            System.out.print("If you would liketo quit type exit: ");
            if ("exit".equalsIgnoreCase(keyboard.nextLine()));

            keyboard.close();
        }
    }
}

在这一点上，我对Java和编码的了解甚少，只有非常基本的命令，所以我不知道哪里出了问题。

Answer 1

进行一些调整，您的程序可以运行。我没有考虑这是否是一个好的解决方案，但是我认为这是您想要做的。因此，现在您可以改进解决方案，如何退出循环，如何使用扫描仪等等。

package Main;
import java.util.Scanner;

public class Assignment {

    public static void main(String[] args) {
        Scanner keyboard = new Scanner(System.in);

        String[] names = new String[10];

        int index = 0;
        while (index<10) {
            index++;
            System.out.print("Home team name: ");
            names[index] = keyboard.nextLine();

            System.out.print("Away team name: ");
            names[index] = keyboard.nextLine();

            System.out.print("Enter home score: ");
            names[index] = keyboard.nextLine();

            System.out.print("Enter away score: ");
            names[index] = keyboard.nextLine();

            System.out.print("If you would like to quit type exit: ");
            if ("exit".equalsIgnoreCase(keyboard.nextLine())) {
                index = 10;
                keyboard.close();
            }
        }
    }
}

Answer 2

在if ("exit".equalsIgnoreCase(keyboard.nextLine()))之后有分号，因此keyboard.close()总是被忽略。

删除符合;的{{1}}

但是关闭输入不会结束while循环。而是添加一个if ("exit".equalsIgnoreCase(keyboard.nextLine()))命令退出循环并在循环后关闭所有情况下的键盘，不仅限于'exit'

Eclipse程序即使没有语法错误也无法运行

2 个答案: