Question

我想按15秒的时间间隔总结以下查询。

select to_char(sample_time,'hh24:mi:ss') as SAMPLE_TIME,nvl(wait_class,'CPU'),count(*) 
from gv$active_session_history 
group by wait_class,sample_time;

结果；

SAMPLE_TIME    WAITS   COUNT
-----------------------------
14:59:00        CPU     3
14:59:02        CPU     1
14:59:08        CPU     2
14:58:11        CPU     2
14:59:18        CPU     1
14:59:24        CPU     2
14:58:29        CPU     2

我要按15秒的间隔求和。我该怎么做？

SAMPLE_TIME    WAITS   COUNT
-----------------------------
14:59:15        CPU     8
14:59:30        CPU     5

Answer 1

使用此功能：

CREATE OR REPLACE FUNCTION MakeInterval(ts IN TIMESTAMP, roundInterval IN INTERVAL DAY TO SECOND) RETURN TIMESTAMP DETERMINISTIC IS
    denom INTEGER;
BEGIN
    IF roundInterval >= INTERVAL '1' HOUR THEN
        denom := EXTRACT(HOUR FROM roundInterval);
        IF MOD(24, denom) <> 0 THEN
            RAISE VALUE_ERROR;
        END IF;
        RETURN TRUNC(ts) + TRUNC(EXTRACT(HOUR FROM ts) / denom) * denom * INTERVAL '1' HOUR;
    ELSIF roundInterval >= INTERVAL '1' MINUTE THEN
        denom := EXTRACT(MINUTE FROM roundInterval);
        IF MOD(60, denom) <> 0 THEN
            RAISE VALUE_ERROR;
        END IF;
        RETURN TRUNC(ts, 'hh') + TRUNC(EXTRACT(MINUTE FROM ts) / denom) * denom * INTERVAL '1' MINUTE;
    ELSE
        denom := EXTRACT(SECOND FROM roundInterval);                
        IF MOD(60, denom) <> 0 THEN
            RAISE VALUE_ERROR;
        END IF;
        RETURN TRUNC(ts, 'mi') + TRUNC(EXTRACT(SECOND FROM ts) / denom) * denom * INTERVAL '1' SECOND;
    END IF;
END MakeInterval;

然后您就可以使用

...
GROUP BY wait_class, MakeInterval(SAMPLE_TIME, INTERVAL '15' SECOND)

Answer 2

这看起来有点hack-ish，但它应该是您想要的。 lpad只是为了获得更好的外观。

编辑：忘记按实际语句而不是 sample_time 分组。现在应该以15秒为间隔进行分组。

select 
    to_char(sample_time, 'hh24:mi:') || lpad(trunc(to_number(to_char(sample_time, 'ss')) / 15) * 15, 2, '0') as SAMPLE_TIME,
    nvl(wait_class, 'CPU') as wait_class,
    count(*) 
from gv$active_session_history 
group by nvl(wait_class, 'CPU'), to_char(sample_time, 'hh24:mi:') || lpad(trunc(to_number(to_char(sample_time, 'ss')) / 15) * 15, 2, '0')

Answer 3

-无法添加评论，因为我的代表非常低

@Wernfried Domscheit向您提供了所有必需的信息，我接受了他的评论，然后简单地按查询的一部分将它们“拍打”到了组中（显然需要在选择语句中添加存储桶定义）

下面的代码将允许您检查Wernfried的回复：

select TO_CHAR(TRUNC(SAMPLE_TIME, 'mi') + TRUNC(EXTRACT(SECOND FROM SAMPLE_TIME) /
EXTRACT(SECOND FROM INTERVAL '15' SECOND)) * EXTRACT(SECOND FROM INTERVAL '15' 
SECOND) *     INTERVAL '1' SECOND,'MM/DD/YYYY HH24:MI:SS') AS TimeBucket
,  nvl(wait_class,'CPU')
,count(*) as NbrRecords
from gv$active_session_history 
GROUP BY TO_CHAR(TRUNC(SAMPLE_TIME, 'mi') + TRUNC(EXTRACT(SECOND FROM SAMPLE_TIME) /
 EXTRACT(SECOND FROM INTERVAL '15' SECOND)) * EXTRACT(SECOND FROM INTERVAL '15' 
SECOND) *     INTERVAL '1' SECOND,'MM/DD/YYYY HH24:MI:SS'), nvl(wait_class,'CPU')
ORDER BY TimeBucket DESC
;

HTH，

B

Oracle按15秒的间隔汇总数据

3 个答案: