Question

我正在尝试使用熊猫从链接中删除00:00:00（HH：MM：SS）。

https://www.z-ratos.com/orical/?from=USD&amount=0&date=2018-10-24 00:00:00

因此，我如何从链接中删除此00:00:00，以便其正常工作。我尝试了这段代码：

import requests
import pandas as pd
from datetime import *

# TO TAKE DATE DIFFERENCE IN LIST
today = datetime.today()
dates = pd.date_range('2018-10-13', today)
#print(dates)

for i in dates:
    #print(i)
    url = 'https://www.z-ratos.com/orical/?from=USD&amount=0&date%s'%i
    print(url)

输出为：

https://www.z-ratos.com/orical/?from=USD&amount=0&date=2018-10-24 00:00:00
    .....
     ......
      ......

必需的输出是：

https://www.z-ratos.com/orical/?from=USD&amount=0&date=2018-10-24

所以请帮忙在此先感谢...

Answer 1

使用strftime("%Y-%m-%d")

例如：

import requests
import pandas as pd
from datetime import *

# TO TAKE DATE DIFFERENCE IN LIST
today = datetime.today()
dates = pd.date_range('2018-10-13', today)
#print(dates)

for i in dates:
    #print(i)
    url = 'https://www.z-ratos.com/orical/?from=USD&amount=0&date%s'%i.strftime("%Y-%m-%d")
    print(url)

Answer 2

将DatetimeIndex.strftime用于字符串：

dates = pd.date_range('2018-10-13', today).strftime('%Y-%m-%d')

然后是format或f-strings：

for i in dates:
    #print(i)
    url = 'https://www.z-ratos.com/orical/?from=USD&amount=0&date={}'.format(i)
    #python 3.6+ solution
    #url = f'https://www.z-ratos.com/orical/?from=USD&amount=0&date={i}'
    print(url)

Answer 3

使用date对象的Datetime方法。要从所有日期中删除时间戳，请执行以下操作：

dates = [d.date() for d in dates]

或者，当您遍历日期时，只需使用i.date()。

如何从字符串中删除00:00:00

3 个答案: