Question

我有代码可以返回任何给定ID（包括给定ID）的最后5个结果。我想要的是，如果没有先前的值等于5，则分别返回带有单词none和00的额外行。

因此，如果代码返回3个结果，则产生2条额外的行，如果代码返回4个结果，则产生1条额外的行。

当前代码：（aaa.FS01 = '12345'）只是ID的示例

SELECT aaa.FS01,
CAST(COUNT(distinct bbb.MG) AS FLOAT)/ convert(varchar(10), DATEDIFF(second ,MIN(TP), MAX(TP))/3600.0) TPDIFF,
22 TAG
FROM TableA aaa
INNER JOIN TableB bbb ON bbb.tpl = aaa.FS01 OR bbb.fpl = aaa.FS01
INNER JOIN TableC ccc ON ccc.id = aaa.FS01
INNER JOIN TableD ddd ON aaa.VG = ddd.gkey
WHERE aaa.FS01 IN (
SELECT TOP 5 ccc.id 
FROM TableA aaa
INNER JOIN TableC ccc ON ccc.id = aaa.FS01
INNER JOIN TableD v ON aaa.VG = ddd.gkey
WHERE ddd.name = (SELECT ddd.name FROM TableA aaa
INNER JOIN TableD v ON aaa.VG = ddd.gkey WHERE aaa.FS01 = '12345')
ORDER BY ccc.ata DESC) 
GROUP BY aaa.FS01, ccc.ata
ORDER BY ccc.ata DESC

当前输出（对于仅返回3个值的FS01）：

FS01    TPDIFF   TAG
12345   30       22
22222   50       22
45122   90       22

预期输出（对于仅返回3个值的FS01）：

FS01    TPDIFF   TAG
12345   30       22
22222   50       22
45122   90       22
none    00       22
none    00       22

当前输出（对于仅返回1个值的FS01）：

FS01    TPDIFF   TAG
74133   30       22

预期输出（对于仅返回1个值的FS01）：

FS01    TPDIFF   TAG
74133   80       22
none    00       22
none    00       22
none    00       22
none    00       22

Answer 1

您可以通过一个查询来做到这一点：

with t as (<your query here>),
     nones as (
      select 'none' as FS01, '00' as TPDIFF, '22' as TAG
      from (values (1), (2), (3), (4), (5))
     )
select top (5) tn.FS01, tn.TPDIFF, tn.TAG
from ((select t.* from t) union all
      nones
     ) tn
order by (case when FS01 = 'none' then 1 else 2 end) as asc;

Answer 2

我会这样声明一个表变量。然后使用一会儿来追加空行。

类似这样的东西：

DECLARE @tbl AS TABLE(FS01 text, TPDIFF text, TAG Text);
INSERT INTO @tbl (FS01, TPDIFF, TAG) 

--your select statement (copied)
SELECT aaa.FS01,
CAST(COUNT(distinct bbb.MG) AS FLOAT)/ convert(varchar(10), DATEDIFF(second ,MIN(TP), MAX(TP))/3600.0) TPDIFF,
22 TAG
FROM TableA aaa
INNER JOIN TableB bbb ON bbb.tpl = aaa.FS01 OR bbb.fpl = aaa.FS01
INNER JOIN TableC ccc ON ccc.id = aaa.FS01
INNER JOIN TableD ddd ON aaa.VG = ddd.gkey
WHERE aaa.FS01 IN (
SELECT TOP 5 ccc.id 
FROM TableA aaa
INNER JOIN TableC ccc ON ccc.id = aaa.FS01
INNER JOIN TableD v ON aaa.VG = ddd.gkey
WHERE ddd.name = (SELECT ddd.name FROM TableA aaa
INNER JOIN TableD v ON aaa.VG = ddd.gkey WHERE aaa.FS01 = '12345')
ORDER BY ccc.ata DESC) 
GROUP BY aaa.FS01, ccc.ata
ORDER BY ccc.ata DESC


declare @cnt as int;
SELECT @cnt = count(*) from @tbl

while @cnt < 5
    BEGIN
        insert into @tbl (FS01, TPDIFF, TAG) VALUES('none', '00', '22');
        select @cnt = @cnt+1;
    end

select top 5 * from @tbl;

SQL Server向结果中添加X行，使其始终等于5行输出

2 个答案: