我有两个鳕鱼,第一个是给父母的,它向孩子发送一个信号(update `guests` set `status`=$1 where `name`=$2'`
),当孩子收到它时,他应该打印他收到的信号。
父代码
SIGUSER1
子代码
#include <stdio.h>
#include <stdlib.h>
#include <sys/wait.h>
#include <unistd.h>
#include <sys/types.h>
void sighand(int);
int main()
{
int cpid, ppid;
ppid = getpid();
printf("My process ID is %d\n", ppid);
FILE *fp1;
fp1 = fopen("cpid.txt", "w+");
cpid = fork();
if ( cpid == 0 ) {
printf("I am the child => PID = %d\n", getpid());
}
else
printf("I am the parent => PID = %d, child ID = %d\n", getpid(), cpid);
fprintf(fp1, "%d\n", cpid);
// kill(cpid, SIGUSR1);//id, signal, send
sigset(SIGUSR2, sighand);
return 0;
}
void sighand(int the_sig){
if (the_sig == SIGUSR2){
printf("sigusr2 received");
exit(1);
}
}
当我启动代码时,它会打印出已创建了进程(子进程),然后在我发送信号时,它不会做任何事情使子进程陷入阻塞或等待,而父进程也不会做任何事情,任何人都可以告诉我在哪里我的代码或逻辑上出错了吗?
答案 0 :(得分:1)
您的代码有几个问题:
getppid()
函数(获取父ID)因此,您可以通过以下方式更正您的代码:
#include <stdio.h>
#include <stdlib.h>
#include <sys/wait.h>
#include <unistd.h>
#include <sys/types.h>
#include <signal.h>
void parent_handler(int the_sig)
{
if (the_sig == SIGUSR2){
printf("sigusr2 received in parent\n");
}
}
void child_handler(int the_sig)
{
if (the_sig == SIGUSR1){
printf("sigusr1 received in child\n");
kill(getppid(), SIGUSR2);
exit(1);
}
}
int child_function()
{
/* prepare to receive signal */
sigset(SIGUSR1,child_handler);
while(1) {
printf("Waiting..");
fflush(stdout);
/* wait for signal */
sigpause(SIGUSR1);
}
return 0;
}
int main()
{
int cpid, ppid;
ppid = getpid();
printf("My process ID is %d\n", ppid);
cpid = fork();
if ( cpid == 0 ) {
printf("I am the child => PID = %d\n", getpid());
child_function();
return 0;
}
else
printf("I am the parent => PID = %d, child ID = %d\n", getpid(), cpid);
/* child will never reach this point */
sleep(1);
/* prepare parent to received signal */
sigset(SIGUSR2, parent_handler);
/* send signal to child */
kill(cpid, SIGUSR1);
sleep(1);
return 0;
}