Question

在phalcon框架中，我想填充相关的下拉类别列表。但是我在代码中遇到了一些问题：

＃1。在选择类别列表->子类别列表上显示：未定义（未使用值填充选项）

＃2。如果数据库没有数据console.log显示：未定义的变量：我的控制器中的resData
＃3。如果选择值为“ 0”的类别，则不会再次禁用子类别列表我在代码中做错了什么？

[Module.php]

subsubsection

[CONTROLLER]

use Phalcon\Mvc\View;
use Phalcon\Mvc\View\Engine\Volt;

$di->setShared('view', function () use ($config){
    $view = new View();
    $view->setViewsDir(APP_PATH . $config->appB->viewsDir);
# Register Volt Template           
    $view->registerEngines(array( 
    ".volt" => function($view, $di) use ($config) {
        $volt = new Volt($view, $di);
        $volt->setOptions(
            array(
                'compiledPath'      => APP_PATH . $config->appB->cacheDir,
                'compiledExtension' => '.php',
                'compiledSeparator' => '_',
                'compileAlways'     => true,
                'autoescape'        => false,
                'stat'              => true
            )
        );
    $compiler = $volt->getCompiler();
    $compiler->addFunction('strtotime','strtotime');

    return $volt;
    }
    ));            
    return $view;
});

[输入电压]

public function entryAction()
{
        $formAction = 'backend/index/insert';
        $this->view->setVar('action',$formAction);
        $this->view->product_title = '';
        $this->view->product_price = '';
        $this->view->product_keyword = '';
        $this->view->product_image = '';
        $this->view->product_desc = '';
        $category = Categories::find();
        $this->view->setVar('categories',$category);                       
        $this->view->pick("index/entry");
}

public function getSubcategoryAction()
{ 
    $id = $this->request->getPost('id');
    $data = Subcat::findBycategory_id($id); 
    $resData = array();    
    foreach($data as $result)
    {
        $resData[] = array('id' => $result->id, 'category_id' => $result->category_id, 'subcategory' => $result->subcategory_name);
    }
    echo(json_encode($resData));       
    //$this->view->setVar('subcategory',$resData);
}

[JQUERY]

Category:<select name="category" id="category">
    <option value="0">Choose Category ...</option>
{% for category in categories %}
    <option value="{{category.id}}">{{category.categoryname}}</option>
{% endfor %}
</select><br/>
sub-Category:<select name="subcategory" id="subcategory" disabled="disabled"><option value="0">Choose Sub-Category ...</option></select>
<br/>
    Products:<select name="products" id="products" disabled="disabled"><option value="0">Choose a Product ...</option></select>
<br/>

Answer 1

请注意，在控制器的第一行中，您正在禁用视图，因此不会处理Volt。在您现在工作时，jQuery仅接收JSON结果，因此您要附加JSON而不是Volt。您必须选择一个路径：要么使用Volt，在这种情况下，您必须在两个操作中都删除第1行并使用参数处理视图，或者继续向jQuery发送JSON数据，并正确设置以处理JSON响应（检查此answer）

在您的情况下，getSubcategoryAction()如下所示：

public function getSubcategoryAction()
{ 
    //$this->view->disable();  //Replaced by: 
    $this->view->setRenderLevel(
        View::LEVEL_ACTION_VIEW
     );        
    $id = $this->request->getPost('id');
    $data = Subcat::findBycategory_id($id);   
    foreach($data as $result)
    {
        $resData[] = array('id' => $result->id, 'category_id' => $result->category_id, 'subcategory' => $result->subcategory_name);
    }

    $this->view->setVar('categories', $resData);

}

这是假设您已在自己的DI中将Volt设置为渲染引擎，并且Volt模板对应于../app/views/index/getSubcategory.phtml，即：

<?php

use Phalcon\Mvc\View;
use Phalcon\Mvc\View\Engine\Volt;

// Register Volt as a service
$di->set(
    'voltService',
    function ($view, $di) {
        $volt = new Volt($view, $di);

        $volt->setOptions(
          [
            'compiledPath'      => '../app/compiled-templates/',
            'compiledExtension' => '.compiled',
          ]
        );

       return $volt;
    }
);

// Register Volt as template engine
$di->set(
    'view',
    function () {
        $view = new View();

        $view->setViewsDir('../app/views/');

        $view->registerEngines(
          [
            '.volt' => 'voltService',
          ]
        );

        return $view;
    }
);

伏特注册代码是从以下位置复制的：https://docs.phalconphp.com/en/3.4/volt根据您的App结构修改目录。

Answer 2

按照此操作，只更新您的代码...

[JQuery]

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.0/jquery.min.js"></script>
<!DOCTYPE html>

<html lang="en" xmlns="http://www.w3.org/1999/xhtml">
<head>
    <meta charset="utf-8" />
    <title></title>
    <script src="Scripts/jquery-3.3.1.min.js"></script>
</head>
<body>
    <form method="post">
        <span name="a">Check it</span>  <input type="checkbox"  id="id_exam_choices_1"  />
        <span name="a">Check it</span>  <input type="checkbox"  id="id_exam_choices_2"  />
<span name="a">Check it</span>  <input type="checkbox"  id="id_exam_choices_3"  />
    </form>
</body>

</html>

依赖于Phalcon的下拉列表填充

2 个答案: